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M21-13

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M21-13  [#permalink]

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New post 16 Sep 2014, 01:10
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  15% (low)

Question Stats:

72% (00:55) correct 28% (00:42) wrong based on 128 sessions

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If all the 10 directors present at a meeting shook hands with each other so that in the end there were no two directors who didn't shake hands, how many handshakes were performed?

A. 30
B. 36
C. 42
D. 45
E. 90

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Re M21-13  [#permalink]

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New post 16 Sep 2014, 01:10
Official Solution:

If all the 10 directors present at a meeting shook hands with each other so that in the end there were no two directors who didn't shake hands, how many handshakes were performed?

A. 30
B. 36
C. 42
D. 45
E. 90

The total number of handshakes will be equal to the number of different pairs possible from these 10 people (one handshake per pair), so \(C^2_{10}=45\).

Answer: D
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: M21-13  [#permalink]

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New post 06 Jul 2016, 06:52
Bunuel wrote:
Official Solution:

If all the 10 directors present at a meeting shook hands with each other so that in the end there were no two directors who didn't shake hands, how many handshakes were performed?

A. 30
B. 36
C. 42
D. 45
E. 90

The total number of handshakes will be equal to the number of different pairs possible from these 10 people (one handshake per pair), so \(C^2_{10}=45\).

Answer: D


Hello Bunuel,
I am making a very silly mistake while solving this problem and similar ones which are there in GMATCLUB tests,
Kindly guide me whats the basic thing I am missing,
1 person does 9 handshakes so 9 people 10 mistakes.
Why is my answer 90 and not 45
I know this s combination problem and should use 10C2 but why is what I am not understanding.
Thanking you in advance.
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Re: M21-13  [#permalink]

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New post 06 Jul 2016, 07:27
89renegade wrote:
Bunuel wrote:
Official Solution:

If all the 10 directors present at a meeting shook hands with each other so that in the end there were no two directors who didn't shake hands, how many handshakes were performed?

A. 30
B. 36
C. 42
D. 45
E. 90

The total number of handshakes will be equal to the number of different pairs possible from these 10 people (one handshake per pair), so \(C^2_{10}=45\).

Answer: D


Hello Bunuel,
I am making a very silly mistake while solving this problem and similar ones which are there in GMATCLUB tests,
Kindly guide me whats the basic thing I am missing,
1 person does 9 handshakes so 9 people 10 mistakes.
Why is my answer 90 and not 45
I know this s combination problem and should use 10C2 but why is what I am not understanding.
Thanking you in advance.


You are double-counting here. Check with smaller numbers to verify.

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_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

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Re: M21-13  [#permalink]

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New post 21 Nov 2017, 06:56
+1 for option D.
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Re: M21-13  [#permalink]

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New post 21 Nov 2017, 08:30
89renegade wrote:
Bunuel wrote:
Official Solution:

If all the 10 directors present at a meeting shook hands with each other so that in the end there were no two directors who didn't shake hands, how many handshakes were performed?

A. 30
B. 36
C. 42
D. 45
E. 90

The total number of handshakes will be equal to the number of different pairs possible from these 10 people (one handshake per pair), so \(C^2_{10}=45\).

Answer: D


Hello Bunuel,
I am making a very silly mistake while solving this problem and similar ones which are there in GMATCLUB tests,
Kindly guide me whats the basic thing I am missing,
1 person does 9 handshakes so 9 people 10 mistakes.
Why is my answer 90 and not 45
I know this s combination problem and should use 10C2 but why is what I am not understanding.
Thanking you in advance.




Hey There,

I would like to give my 2 cents.
Think of these questions in general way.
Lets take example of premier league (for those who are not aware.. it is professional top tier football competition in England)..
There are 20 teams and each teams plays 2 matched with every other team (home and Away).
In total there will be 20 * 19 matches == 380 matches.

Now coming to our question..
Here 10 people are there and so there will be 10 * 9 total handshakes..
But a handshake is same if you look from both persons prospective (i.e, from person 1 or from person 2).
So we have to half it... 10*9 / 2 = 45.
Using this concept we got the formula of 10C2.

Hope it helps.
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Re: M21-13 &nbs [#permalink] 21 Nov 2017, 08:30
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