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If all 10 directors present at a meeting shook hands with each other, how many handshakes took place?

\(10\) people each shook hands with \(9\) other people.

At the same time, when one person shakes hands with a second person, the second also shakes hands with the first. So, there were not \(90\) handshakes. There were \(\frac{90}{2}\) handshakes.

Alternatively, we can say that, to count handshakes, each of which involves \(2\) people, we can simply determine how many ways there are to select \(2\) people out of \(10\).

\(10C2 = \frac{10 × 9}{2!} = 45\)

A. 30
B. 36
C. 42
D. 45
E. 90


Correct answer: D
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