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M21-19

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M21-19  [#permalink]

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New post 16 Sep 2014, 01:11
00:00
A
B
C
D
E

Difficulty:

  85% (hard)

Question Stats:

40% (01:16) correct 60% (12:54) wrong based on 159 sessions

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Re M21-19  [#permalink]

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New post 16 Sep 2014, 01:11
1
Official Solution:

Statements (1) and (2) combined are insufficient. Consider \(p = \frac{1}{3}\), \(q = \frac{1}{2}\) (the answer is "no") and \(p = -\frac{1}{2}\), \(q = -\frac{1}{3}\) (the answer is "yes"). We must remember that \(p\) and \(q\) are not necessarily positive.

Answer: E
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Re: M21-19  [#permalink]

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New post 21 Jun 2015, 09:26
Hi Bunuel,
Can we not look at this way?

p+q>1/p+1/q can be re-written as (p+q)pq>(p+q). Cancelling (p+q) on both sides, the question can be re-written as is pq>1?

St II says pq<1 and so St II is sufficient.
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Re: M21-19  [#permalink]

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New post 21 Jun 2015, 10:57
1
dpbe25 wrote:
Hi Bunuel,
Can we not look at this way?

p+q>1/p+1/q can be re-written as (p+q)pq>(p+q). Cancelling (p+q) on both sides, the question can be re-written as is pq>1?

St II says pq<1 and so St II is sufficient.


1. You cannot multiply both sides by pq because we don't know whether it's positive or negative (if it's negative you should flip the sign).
2. You cannot reduce by p+q by the same reason.

Check here: is-p-q-1-p-1-q-154268.html#p1235382
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Re: M21-19  [#permalink]

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New post 22 Jun 2015, 08:05
Thanks Bunuel for the explanation.
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Re: M21-19  [#permalink]

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New post 03 Jul 2015, 05:42
Bunuel wrote:
dpbe25 wrote:
Hi Bunuel,
Can we not look at this way?

p+q>1/p+1/q can be re-written as (p+q)pq>(p+q). Cancelling (p+q) on both sides, the question can be re-written as is pq>1?

St II says pq<1 and so St II is sufficient.


1. You cannot multiply both sides by pq because we don't know whether it's positive or negative (if it's negative you should flip the sign).
2. You cannot reduce by p+q by the same reason.

Check here: is-p-q-1-p-1-q-154268.html#p1235382


Hi Bunuel,

In this kind of question is it helpfull to try tu reduce the question stem or is better to try numbers directly to the statements?, for instance I try to reduce and the question stem result in (pq)squared - 1 > 0

Thanks a lot.

Regards.

Luis Navarro
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Re: M21-19  [#permalink]

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New post 03 Jul 2015, 06:09
luisnavarro wrote:
Bunuel wrote:
dpbe25 wrote:
Hi Bunuel,
Can we not look at this way?

p+q>1/p+1/q can be re-written as (p+q)pq>(p+q). Cancelling (p+q) on both sides, the question can be re-written as is pq>1?

St II says pq<1 and so St II is sufficient.


1. You cannot multiply both sides by pq because we don't know whether it's positive or negative (if it's negative you should flip the sign).
2. You cannot reduce by p+q by the same reason.

Check here: is-p-q-1-p-1-q-154268.html#p1235382


Hi Bunuel,

In this kind of question is it helpfull to try tu reduce the question stem or is better to try numbers directly to the statements?, for instance I try to reduce and the question stem result in (pq)squared - 1 > 0

Thanks a lot.

Regards.

Luis Navarro
Looking for 700


First of all if you manipulate with the inequality you don't get (pq)^2 - 1.

Next, it depends on a question and you math skills what approach to choose.

Check this post for inequality DS approaches: time-management-when-testing-cases-in-ds-200020.html#p1538771

Also check below links:

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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
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Re: M21-19  [#permalink]

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New post 10 Jun 2016, 10:56
Hi bunuel,

I too worked with the same approach. Additionally i also assumed "what if one of the numbers equaled 0" if that was the case then equation in question statement would have an undefined side RHS with 1/0. Based on that i quickly eliminated. is that the right approach considering nothing is mentioned about both numbers being non-zero?
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Re: M21-19  [#permalink]

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New post 13 Sep 2017, 14:26
Senthil7 wrote:
Hi bunuel,

I too worked with the same approach. Additionally i also assumed "what if one of the numbers equaled 0" if that was the case then equation in question statement would have an undefined side RHS with 1/0. Based on that i quickly eliminated. is that the right approach considering nothing is mentioned about both numbers being non-zero?



It is safe to assume that both P and Q will not be equal to 0 since that if that were the case it would lead to "undefined" results. I think the assumption is to understand that such scenarios don't exist within the bounds of the GMAT Quantitative Reasoning world. :roll:
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Re: M21-19  [#permalink]

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New post 29 Nov 2017, 03:04
The answer must be option E. You can have different cases here. Both +ve, both -ve , & one +ve and one -ve. Try out with all the three cases and you will realise that both together are not sufficient.
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Re: M21-19 &nbs [#permalink] 29 Nov 2017, 03:04
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