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M22-02

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M22-02 [#permalink]

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If the diagonals of rectangle \(ABCD\) (\(AB \gt BC\)) cross at point \(E\), what is the value of \(\angle AEB\) ?


(1) The value of \(\angle EDC\) is 15 degrees

(2) The value of \(\angle ACB\) is 75 degrees
[Reveal] Spoiler: OA

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New post 18 Feb 2015, 06:14
Request you to please explain the answer more vividly.

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Re M22-02 [#permalink]

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New post 18 Aug 2015, 20:53
I think this is a high-quality question and the explanation isn't clear enough, please elaborate. Kindly request to elaborate on the solution as to how in both the statements angle AEB is derived by subtracting 180 degree from the given angles in the statements and what rule of quadrilaterals is applied in the question.It would be better if a diagram can be drawn.

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Re: M22-02 [#permalink]

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New post 19 Aug 2015, 04:53
Hi Bunuel,

What properties are applied here ? Is there any alternative here ?

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M22-02 [#permalink]

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The problem says it's a rectangle. A rectangle's diagonals bisect each other and are equal in length, so if you draw a rectangle and draw in the diagonals, you'll get 4 isosceles triangles. Both statements give one angle of the two angles between the base and the equal sides, so you can calculate the third angle from both statements and get to AEB.

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New post 15 Oct 2015, 05:19
I think this is a high-quality question and the explanation isn't clear enough, please elaborate.

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Re: M22-02 [#permalink]

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New post 29 Nov 2015, 00:01
i know its real late to answer... diagonals of rectangle bisect each other ... so both statements give us the 2 angles of the smaller triangles ....

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New post 25 Dec 2015, 09:00
I think this the explanation isn't clear enough, please elaborate. Could you please offer a drawing as I can't understand it.

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Re: M22-02 [#permalink]

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New post 26 Dec 2017, 08:09
+1 for D. Use the property that diagonals of a rectangle bisect one another. Both statements are sufficient individually. Hence option D.
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Re: M22-02   [#permalink] 26 Dec 2017, 08:09
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