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16 Sep 2014, 00:15



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09 Nov 2014, 20:42
Thanks for Explanation! I did not understand following part " The roots are x=0 and x=1, \("\gt"\) sign means that the given inequality holds true for: \(x \lt 0\) and \(x \gt 1\)." I thought \(x(x1) \gt 0\) would mean \(x \gt 0\) and \(x \gt 1\) Please suggest. Also how did we get 1 as final answer. As per statement (2) \(x \gt 1\). Thanks Bunuel wrote: Official Solution:
(1) \(x^4 = x\). This statement implies that \(x=1\), \(x=0\), or \(x=1\). Not sufficient. (2) \(x^2 \gt x\). Rearrange and factor out \(x\) to get \(x(x1) \gt 0\). The roots are \(x=0\) and \(x=1\), "\(\gt\)" sign means that the given inequality holds true for: \(x \lt 0\) and \(x \gt 1\). Not sufficient. (1)+(2) The only value of \(x\) from (1) which is in the range from (2) is \(x=1\). Sufficient.
Answer: C



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10 Nov 2014, 01:57
Sky78 wrote: Thanks for Explanation! I did not understand following part " The roots are x=0 and x=1, \("\gt"\) sign means that the given inequality holds true for: \(x \lt 0\) and \(x \gt 1\)." I thought \(x(x1) \gt 0\) would mean \(x \gt 0\) and \(x \gt 1\) Please suggest. Also how did we get 1 as final answer. As per statement (2) \(x \gt 1\). Thanks Bunuel wrote: Official Solution:
(1) \(x^4 = x\). This statement implies that \(x=1\), \(x=0\), or \(x=1\). Not sufficient. (2) \(x^2 \gt x\). Rearrange and factor out \(x\) to get \(x(x1) \gt 0\). The roots are \(x=0\) and \(x=1\), "\(\gt\)" sign means that the given inequality holds true for: \(x \lt 0\) and \(x \gt 1\). Not sufficient. (1)+(2) The only value of \(x\) from (1) which is in the range from (2) is \(x=1\). Sufficient.
Answer: C Check links below. Solving Quadratic Inequalities  Graphic Approach: solvingquadraticinequalitiesgraphicapproach170528.htmlInequality tips: tipsandhintsforspecificquanttopicswithexamples172096.html#p1379270
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21 Jun 2016, 06:13
I think this is a highquality question and the explanation isn't clear enough, please elaborate. Not able to understand the explanation



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27 Dec 2017, 07:31
+1 for C. From the first statement x=1,0, or 1. From second statement , x<0 or x>1. Each statement alone is not sufficient. Combine the two, x=1. Hence option C.
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Bunuel wrote: Sky78 wrote: Thanks for Explanation! I did not understand following part " The roots are x=0 and x=1, \("\gt"\) sign means that the given inequality holds true for: \(x \lt 0\) and \(x \gt 1\)." I thought \(x(x1) \gt 0\) would mean \(x \gt 0\) and \(x \gt 1\) Please suggest. Also how did we get 1 as final answer. As per statement (2) \(x \gt 1\). Thanks Bunuel wrote: Official Solution:
(1) \(x^4 = x\). This statement implies that \(x=1\), \(x=0\), or \(x=1\). Not sufficient. (2) \(x^2 \gt x\). Rearrange and factor out \(x\) to get \(x(x1) \gt 0\). The roots are \(x=0\) and \(x=1\), "\(\gt\)" sign means that the given inequality holds true for: \(x \lt 0\) and \(x \gt 1\). Not sufficient. (1)+(2) The only value of \(x\) from (1) which is in the range from (2) is \(x=1\). Sufficient.
Answer: C Check links below. Solving Quadratic Inequalities  Graphic Approach: http://gmatclub.com/forum/solvingquadr ... 70528.htmlInequality tips: http://gmatclub.com/forum/tipsandhint ... l#p1379270Hi Bunuel, I too have exactly the same question as the previous person...I went through the links provided and still cannot understand why in statement 2, x is not either greater than 0 or greater than 1. I then got confused as to how you got to the answer being x= (1). Would really appreciate a breakdown of the above queries please. Thanks, Tosin



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ttaiwo wrote: Hi Bunuel,
I too have exactly the same question as the previous person...I went through the links provided and still cannot understand why in statement 2, x is not either greater than 0 or greater than 1. I then got confused as to how you got to the answer being x= (1).
Would really appreciate a breakdown of the above queries please.
Thanks,
Tosin This is explained in detail in the links provided. x > 0 or x > 1 doe not make any sense. Is x > 0? So, could it be 0.5? Or is x > 1? \(x(x1) \gt 0\) > x and x  1 have the same sign. x > 0 and x  1 > 0 > x > 0 and x > 1. Simultaneously to be true x > 1 has to be true. x < 0 and x  1 < 0 > x < 0 and x < 1. Simultaneously to be true x < 0 has to be true. So, \(x(x1) \gt 0\) is true for x < 0 and x > 1.
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Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
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Re: M2203
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17 Feb 2018, 02:58
Bunuel wrote: ttaiwo wrote: Hi Bunuel,
I too have exactly the same question as the previous person...I went through the links provided and still cannot understand why in statement 2, x is not either greater than 0 or greater than 1. I then got confused as to how you got to the answer being x= (1).
Would really appreciate a breakdown of the above queries please.
Thanks,
Tosin This is explained in detail in the links provided. x > 0 or x > 1 doe not make any sense. Is x > 0? So, could it be 0.5? Or is x > 1? \(x(x1) \gt 0\) > x and x  1 have the same sign. x > 0 and x  1 > 0 > x > 0 and x > 1. Simultaneously to be true x > 1 has to be true. x < 0 and x  1 < 0 > x < 0 and x < 1. Simultaneously to be true x < 0 has to be true. So, \(x(x1) \gt 0\) is true for x < 0 and x > 1. Thanks a lot...now understood.



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Re: M2203
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10 Jul 2018, 22:17
is the absolute value of zero, zero?
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10 Jul 2018, 22:22



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16 Nov 2018, 00:37
wouldnt this ans insufficient when x=2,2 if this is the case, then x could still satisfy both condition.
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16 Nov 2018, 01:01










