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# M22-05

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Math Expert
Joined: 02 Sep 2009
Posts: 52971

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16 Sep 2014, 00:16
00:00

Difficulty:

25% (medium)

Question Stats:

75% (01:38) correct 25% (02:01) wrong based on 103 sessions

The rental charge for a car is 34 cents for the first $$\frac{1}{4}$$ mile driven and 6 cents for every $$\frac{1}{5}$$ mile driven over the initial $$\frac{1}{4}$$ mile. If a man paid $1.24 in rental charges, how many miles did he drive? A. 2.50 B. 3.00 C. 3.25 D. 3.75 E. 4.00 _________________ Math Expert Joined: 02 Sep 2009 Posts: 52971 Re M22-05 [#permalink] ### Show Tags 16 Sep 2014, 00:16 1 Official Solution: The rental charge for a car is 34 cents for the first $$\frac{1}{4}$$ mile driven and 6 cents for every $$\frac{1}{5}$$ mile driven over the initial $$\frac{1}{4}$$ mile. If a man paid$1.24 in rental charges, how many miles did he drive?

A. 2.50
B. 3.00
C. 3.25
D. 3.75
E. 4.00

The driver went $$(\frac{1.24 - 0.34}{0.06})/5 = 3$$ miles in excess of the first fourth of a mile. The overall distance is 3.25 miles.

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Intern
Joined: 28 Mar 2014
Posts: 18

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14 Oct 2015, 18:08
Unable to come at this equation ....total fare= No. of km * Fare / Km----->1.24 = 0.34 + 0.06*(1/5) X
Here X is the No of 1/5 interval.So X= 75 n total distance = 1/5 X = 15+0.25=15.25

The above equation differs from my equation. Pls let me know where i am wrong
Intern
Joined: 02 Oct 2014
Posts: 8

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12 Jul 2016, 04:21
suyashtcs wrote:
Unable to come at this equation ....total fare= No. of km * Fare / Km----->1.24 = 0.34 + 0.06*(1/5) X
Here X is the No of 1/5 interval.So X= 75 n total distance = 1/5 X = 15+0.25=15.25

The above equation differs from my equation. Pls let me know where i am wrong

The equation is, where x = total miles

-> 124 = 34 + (6)(5)(x-0.25)

solve for x

Since the charge is 6 cents for 1/5 mile, it will be 30 cents for the entire mile. I think thats where you're making the error. Also, i didn't see where you are subtracting the 0.25 miles.

Cheers
Manager
Joined: 14 Oct 2012
Posts: 163

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16 Apr 2017, 19:46
2
Elaborating further on what kaaaaku said:
1.24 - 0.34 = 90 cents left.
Given:
(1/5)th mile cost = 6 cents
1 mile cost = ? => 6/(1/5) = 6*5 = 30 cents.
Therefore,
1 mile = 30 cents
?------= 90 cents
90/30 = 3 miles.
Total miles = 3.25 miles. | C
Intern
Joined: 28 May 2016
Posts: 2

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14 Aug 2017, 07:35
The only mistake you are making after obtaining 15 intervals of 1/5 - is that you are considering it to be 15 miles whereas its 3 miles (15 intervals of 1/5 mile each equals 3 miles ). 3 miles + 0.25 mile is 3.25 mile.

Hope that helps
PS: I made the same mistake
Intern
Joined: 28 Jul 2016
Posts: 40
Location: India
Concentration: General Management, Marketing
WE: Operations (Retail Banking)

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29 Dec 2017, 07:30
3.25 miles \$1.24-34 cents = 90 cents,
6 cents for 0.20 miles so 90 cents for 3 miles. So overall 3.25 miles
Re: M22-05   [#permalink] 29 Dec 2017, 07:30
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# M22-05

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