Summer is Coming! Join the Game of Timers Competition to Win Epic Prizes. Registration is Open. Game starts Mon July 1st.

It is currently 21 Jul 2019, 04:33

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

M22-08

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 56306
M22-08  [#permalink]

Show Tags

New post 16 Sep 2014, 01:16
1
12
00:00
A
B
C
D
E

Difficulty:

  95% (hard)

Question Stats:

30% (02:04) correct 70% (01:54) wrong based on 131 sessions

HideShow timer Statistics


Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 56306
Re M22-08  [#permalink]

Show Tags

New post 16 Sep 2014, 01:16
Official Solution:


What is the probability that one of the two integers randomly selected from range 20-29, inclusive, is prime and the other is a multiple of 3?

(The numbers are selected independently of each other, i.e. they can be equal)


A. 0.06
B. 0.12
C. 0.15
D. 0.18
E. 0.20


Prime integers: 23 and 29. Multiples of 3: 21, 24, and 27.

The probability that the first number is prime while the second is a multiple of \(3 = \frac{2}{10} \frac{3}{10} = 0.06\).

The probability that the first number is a multiple of 3 while the second is prime \(= \frac{3}{10} \frac{2}{10} = 0.06\).

The probability that one of the two integers is prime and the other is a multiple of \(3 = 0.06 + 0.06 = 0.12\).


Answer: B
_________________
Intern
Intern
avatar
Joined: 27 Sep 2015
Posts: 15
Re: M22-08  [#permalink]

Show Tags

New post 03 Apr 2016, 06:15
Hi Bunuel

I was wondering why the order of the selection matters here ?


Thanks

Bunuel wrote:
Official Solution:


What is the probability that one of the two integers randomly selected from range 20-29 is prime and the other is a multiple of 3?

(The numbers are selected independently of each other, i.e. they can be equal)


A. 0.06
B. 0.12
C. 0.15
D. 0.18
E. 0.20


Prime integers: 23 and 29. Multiples of 3: 21, 24, and 27.

The probability that the first number is prime while the second is a multiple of \(3 = \frac{2}{10} \frac{3}{10} = 0.06\).

The probability that the first number is a multiple of 3 while the second is prime \(= \frac{3}{10} \frac{2}{10} = 0.06\).

The probability that one of the two integers is prime and the other is a multiple of \(3 = 0.06 + 0.06 = 0.12\).


Answer: B
Math Expert
User avatar
V
Joined: 02 Aug 2009
Posts: 7763
Re: M22-08  [#permalink]

Show Tags

New post 04 Apr 2016, 06:38
1
3
Michael KC Chen wrote:
Hi Bunuel

I was wondering why the order of the selection matters here ?


Thanks

Bunuel wrote:
Official Solution:


What is the probability that one of the two integers randomly selected from range 20-29 is prime and the other is a multiple of 3?

(The numbers are selected independently of each other, i.e. they can be equal)


A. 0.06
B. 0.12
C. 0.15
D. 0.18
E. 0.20


Prime integers: 23 and 29. Multiples of 3: 21, 24, and 27.

The probability that the first number is prime while the second is a multiple of \(3 = \frac{2}{10} \frac{3}{10} = 0.06\).

The probability that the first number is a multiple of 3 while the second is prime \(= \frac{3}{10} \frac{2}{10} = 0.06\).

The probability that one of the two integers is prime and the other is a multiple of \(3 = 0.06 + 0.06 = 0.12\).


Answer: B


Hi,
more than often follow this rule if in doubt..
1) If you are picking two simultaneously/together, you do not have any order in place..
2) whenever you are picking two with/ without repetition, it can be picked as either A and B or B and A..
_________________
Manager
Manager
avatar
B
Joined: 03 Dec 2014
Posts: 99
Location: India
Concentration: General Management, Leadership
GMAT 1: 620 Q48 V27
GPA: 1.9
WE: Engineering (Energy and Utilities)
Re: M22-08  [#permalink]

Show Tags

New post 04 Apr 2016, 08:11
chetan2u wrote:
Michael KC Chen wrote:
Hi Bunuel

I was wondering why the order of the selection matters here ?


Thanks

Bunuel wrote:
Official Solution:


What is the probability that one of the two integers randomly selected from range 20-29 is prime and the other is a multiple of 3?

(The numbers are selected independently of each other, i.e. they can be equal)


A. 0.06
B. 0.12
C. 0.15
D. 0.18
E. 0.20


Prime integers: 23 and 29. Multiples of 3: 21, 24, and 27.

The probability that the first number is prime while the second is a multiple of \(3 = \frac{2}{10} \frac{3}{10} = 0.06\).

The probability that the first number is a multiple of 3 while the second is prime \(= \frac{3}{10} \frac{2}{10} = 0.06\).

The probability that one of the two integers is prime and the other is a multiple of \(3 = 0.06 + 0.06 = 0.12\).


Answer: B


Hi,
more than often follow this rule if in doubt..
1) If you are picking two simultaneously/together, you do not have any order in place..
2) whenever you are picking two with/ without repetition, it can be picked as either A and B or B and A..




what is wrong when I do:
(2C1 x 3C1)/(10C2).
Please explain.
Math Expert
User avatar
V
Joined: 02 Aug 2009
Posts: 7763
Re: M22-08  [#permalink]

Show Tags

New post 04 Apr 2016, 08:24
1
1
robu wrote:
chetan2u wrote:



what is wrong when I do:
(2C1 x 3C1)/(10C2).
Please explain.


Hi ,
two errors
1) 10C2 is wrong because it is given that the same number can be picked up again..
In other words it is with REPLACEMENT, that is number will remain 10 each time..
so total ways will be 10*10

2) 2C1 * 3C2..
there are two ways here
2C1*3C1 OR 3C1*2C1 so two ways
2C1*3C1*2
_________________
Current Student
avatar
B
Joined: 08 Jan 2015
Posts: 75
GMAT ToolKit User
Re: M22-08  [#permalink]

Show Tags

New post 07 Sep 2016, 00:00
chetan2u wrote:
Michael KC Chen wrote:
Hi Bunuel

I was wondering why the order of the selection matters here ?


Thanks

Bunuel wrote:
Official Solution:


What is the probability that one of the two integers randomly selected from range 20-29 is prime and the other is a multiple of 3?

(The numbers are selected independently of each other, i.e. they can be equal)


A. 0.06
B. 0.12
C. 0.15
D. 0.18
E. 0.20


Prime integers: 23 and 29. Multiples of 3: 21, 24, and 27.

The probability that the first number is prime while the second is a multiple of \(3 = \frac{2}{10} \frac{3}{10} = 0.06\).

The probability that the first number is a multiple of 3 while the second is prime \(= \frac{3}{10} \frac{2}{10} = 0.06\).

The probability that one of the two integers is prime and the other is a multiple of \(3 = 0.06 + 0.06 = 0.12\).


Answer: B


Hi,
more than often follow this rule if in doubt..
1) If you are picking two simultaneously/together, you do not have any order in place..
2) whenever you are picking two with/ without repetition, it can be picked as either A and B or B and A..


It's not actually like that. Check this thread (probability-of-simultaneous-events-veritas-vs-mgat-105994-20.html)
Picking simultaneously is the same as picking one by one without replacement. In any case you need to multiply by the possible number of combinations.
The only case, when you don't need to multiply is when the order is strictly set - for instance, what's the probability that the FIRST number will be prime and the second will be a multiple of 3.
Intern
Intern
avatar
B
Joined: 09 Jul 2016
Posts: 17
GMAT 1: 730 Q50 V39
Reviews Badge
Re: M22-08  [#permalink]

Show Tags

New post 27 May 2017, 07:36
Can we get a confirmation that whether 0.06 is the answer or 0.12?

I am not sure whether we have to count the probability twice - i.e. for each case.

@Bunnel - can you please confirm.
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 56306
Re: M22-08  [#permalink]

Show Tags

New post 27 May 2017, 08:49
Intern
Intern
avatar
B
Joined: 01 Mar 2016
Posts: 1
Re: M22-08  [#permalink]

Show Tags

New post 10 Jul 2017, 08:37
I don't agree with the answer - if order is matter then it matter for both number of desirable events and for total number of events. SO total number of events is not 10x10 but 10x10x2 and desirable events are 3x4x2 also ! Then the answer is 0.06

The reply should be wrong here
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 56306
Re: M22-08  [#permalink]

Show Tags

New post 10 Jul 2017, 11:50
alexxko wrote:
I don't agree with the answer - if order is matter then it matter for both number of desirable events and for total number of events. SO total number of events is not 10x10 but 10x10x2 and desirable events are 3x4x2 also ! Then the answer is 0.06

The reply should be wrong here


This is not right. The order does matter - (prime, multiple of 3) and (multiple of 3, prime) are tow different cases. The reasoning as to why it should be 10*10*2 is not correct and not clear. For both cases we are choosing from 10 numbers, that's why it is 2/10*3/10 + 3/10*2/10.
_________________
SVP
SVP
User avatar
V
Joined: 26 Mar 2013
Posts: 2284
Reviews Badge CAT Tests
Re: M22-08  [#permalink]

Show Tags

New post 11 Jul 2017, 00:44
1
Bunuel wrote:
What is the probability that one of the two integers randomly selected from range 20-29 is prime and the other is a multiple of 3?

(The numbers are selected independently of each other, i.e. they can be equal)


A. 0.06
B. 0.12
C. 0.15
D. 0.18
E. 0.20


Dear Bunuel,

I rarely post about phrasing your question but if you add word 'inclusive' after range 20-29, it would be clear.

Thanks
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 56306
Re: M22-08  [#permalink]

Show Tags

New post 11 Jul 2017, 02:29
Mo2men wrote:
Bunuel wrote:
What is the probability that one of the two integers randomly selected from range 20-29 is prime and the other is a multiple of 3?

(The numbers are selected independently of each other, i.e. they can be equal)


A. 0.06
B. 0.12
C. 0.15
D. 0.18
E. 0.20


Dear Bunuel,

I rarely post about phrasing your question but if you add word 'inclusive' after range 20-29, it would be clear.

Thanks


Edited as suggested. Thank you.
_________________
Senior Manager
Senior Manager
User avatar
S
Joined: 08 Jun 2015
Posts: 421
Location: India
GMAT 1: 640 Q48 V29
GMAT 2: 700 Q48 V38
GPA: 3.33
Reviews Badge
Re: M22-08  [#permalink]

Show Tags

New post 03 Jan 2018, 08:58
chetan2u wrote:
robu wrote:
chetan2u wrote:



what is wrong when I do:
(2C1 x 3C1)/(10C2).
Please explain.


Hi ,
two errors
1) 10C2 is wrong because it is given that the same number can be picked up again..
In other words it is with REPLACEMENT, that is number will remain 10 each time..
so total ways will be 10*10

2) 2C1 * 3C2..
there are two ways here
2C1*3C1 OR 3C1*2C1 so two ways
2C1*3C1*2


Thanks for the explanation !!!
_________________
" The few , the fearless "
Intern
Intern
User avatar
B
Joined: 27 Jul 2017
Posts: 19
Location: Spain
Schools: IMD '20
GMAT 1: 570 Q42 V27
GPA: 2.9
Re: M22-08  [#permalink]

Show Tags

New post 04 Jan 2018, 03:55
What must change in the question stem, in order the result to be 0.06?
This is, no need to sum both probabilities.
Please clarify!
Thanks
Intern
Intern
avatar
B
Joined: 19 Nov 2012
Posts: 27
Re: M22-08  [#permalink]

Show Tags

New post 31 Jan 2018, 00:14
Hello Bunuel:
Bunuel wrote:
alexxko wrote:
I don't agree with the answer - if order is matter then it matter for both number of desirable events and for total number of events. SO total number of events is not 10x10 but 10x10x2 and desirable events are 3x4x2 also ! Then the answer is 0.06

The reply should be wrong here


This is not right. The order does matter - (prime, multiple of 3) and (multiple of 3, prime) are tow different cases. The reasoning as to why it should be 10*10*2 is not correct and not clear. For both cases we are choosing from 10 numbers, that's why it is 2/10*3/10 + 3/10*2/10.


Can you please explain why does order matter here? In other words, how is 23, 27 different from 27, 23 as in both cases it's the same prime number and the same multiple of 3 that's being counted.

Thanks!
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 56306
Re: M22-08  [#permalink]

Show Tags

New post 31 Jan 2018, 02:00
sanjay1810 wrote:
Hello Bunuel:
Bunuel wrote:
alexxko wrote:
I don't agree with the answer - if order is matter then it matter for both number of desirable events and for total number of events. SO total number of events is not 10x10 but 10x10x2 and desirable events are 3x4x2 also ! Then the answer is 0.06

The reply should be wrong here


This is not right. The order does matter - (prime, multiple of 3) and (multiple of 3, prime) are tow different cases. The reasoning as to why it should be 10*10*2 is not correct and not clear. For both cases we are choosing from 10 numbers, that's why it is 2/10*3/10 + 3/10*2/10.


Can you please explain why does order matter here? In other words, how is 23, 27 different from 27, 23 as in both cases it's the same prime number and the same multiple of 3 that's being counted.

Thanks!


The point is that those are two different events. Imagine that there are 10 balls with integer values from 20 through 29 on them. We are picking two balls with replacement. The case when the first ball has a prime number on it and the second ball has a multiple of 3 on it is a different event from a case when the first ball has a multiple of 3 on it and the second ball has a prime number on it.
_________________
Senior Manager
Senior Manager
User avatar
G
Joined: 13 Feb 2018
Posts: 421
GMAT 1: 640 Q48 V28
Premium Member
Re: M22-08  [#permalink]

Show Tags

New post 25 Mar 2019, 12:26
I arrived at

(\(\frac{2}{10}\)*\(\frac{3}{10}\))*2
and everything seemed so easy with this 95% hard question ... BUT

The Ozone layer became thinner, The moon showed the dark side and my brain decided that 2/10=1/2

Ended up - Wrong

I coursed math
-**** this sh@t - I shouted throwing papers away ...
Several seconds later:
-I have to pass - gathering my goddamn papers again

Peace of mind, Peace of mind, Peace of mind
GMAT Club Bot
Re: M22-08   [#permalink] 25 Mar 2019, 12:26
Display posts from previous: Sort by

M22-08

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  

Moderators: chetan2u, Bunuel






Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne