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If after a number was added to a set consisting of all distinct one-digit prime integers, the median of the set grew by 25%, which of the following cannot be the value of the number added?

A. 4.8 B. 5.0 C. \(\sqrt{29}\) D. 7.7 E. \(\frac{49}{4}\)

If after a number was added to a set consisting of all distinct one-digit prime integers, the median of the set grew by 25%, which of the following cannot be the value of the number added?

A. 4.8 B. 5.0 C. \(\sqrt{29}\) D. 7.7 E. \(\frac{49}{4}\)

The original set was \(\{2, 3, 5, 7\}\). Its median was \(\frac{3 + 5}{2} = 4\). The median of the new set \(= 4*1.25 = 5\). Thus, the number added cannot be less than 5.

It´s not clear that the set has all 4 one-digit integers that are prime. One may understand that all items in the set are one digit integers (which would give you {2,3} or {3,5} or {2,3,5}.... just the way it´s written there is room for misunderstanding...

It´s not clear that the set has all 4 one-digit integers that are prime. One may understand that all items in the set are one digit integers (which would give you {2,3} or {3,5} or {2,3,5}.... just the way it´s written there is room for misunderstanding...

Also, nowhere is it mentioned that all of them are positive.

It´s not clear that the set has all 4 one-digit integers that are prime. One may understand that all items in the set are one digit integers (which would give you {2,3} or {3,5} or {2,3,5}.... just the way it´s written there is room for misunderstanding...

Also, nowhere is it mentioned that all of them are positive.

Only positive integers can be primes.
_________________

hi Brunel how can you pick these numbers.For example if set is 2,3,5 then median is 3.after adding x median will become 3.75 so as per your statement number can't be less than 3.75

kindly clear where I am going wrong in my understanding

hi Brunel how can you pick these numbers.For example if set is 2,3,5 then median is 3.after adding x median will become 3.75 so as per your statement number can't be less than 3.75

kindly clear where I am going wrong in my understanding

The question says that the set consists of single-digit prime integers. There are four single digit primes: 2, 3, 5, and 7. So, the set is {2, 3, 5, 7} not {2, 3, 5}
_________________

I think this is a poor-quality question. It says all distinct one digit prime numbers, however it can be unclear. I understood it as ALL the numbers in the set were distinict prime digits, not that they set included ALL the prime single digits

If after a number was added to a set consisting of all distinct one-digit prime integers, the median of the set grew by 25%, which of the following cannot be the value of the number added?

A. 4.8 B. 5.0 C. \(\sqrt{29}\) D. 7.7 E. \(\frac{49}{4}\)

The original set was \(\{2, 3, 5, 7\}\). Its median was \(\frac{3 + 5}{2} = 4\). The median of the new set \(= 4*1.25 = 5\). Thus, the number added cannot be less than 5.

Answer: A

since the new median is 5, all options except B are wrong....????

in other words, if the question mentioned that the median grew by atleast 35%, A would be the answer.

You are wrong.

The original set = {2, 3, 5, 7}. The original median = 4.

B. New number = 5; New set = {2, 3, 5, 5, 7}. New median = 5.

C. New number = \(\sqrt{29}\); New set = 2, 3, 5, \(\sqrt{29}\), 7}. New median = 5.

D. New number = 7.7; New set = {2, 3, 5, 7, 7.7}. New median = 5.

E. New number = \(\frac{49}{4}\); New set = {2, 3, 5, 7, 49/4}. New median = 5.
_________________

If after a number was added to a set consisting of all distinct one-digit prime integers, the median of the set grew by 25%, which of the following cannot be the value of the number added?

A. 4.8 B. 5.0 C. \(\sqrt{29}\) D. 7.7 E. \(\frac{49}{4}\)

The original set was \(\{2, 3, 5, 7\}\). Its median was \(\frac{3 + 5}{2} = 4\). The median of the new set \(= 4*1.25 = 5\). Thus, the number added cannot be less than 5.

Answer: A

since the new median is 5, all options except B are wrong....????

in other words, if the question mentioned that the median grew by atleast 35%, A would be the answer.

You are wrong.

The original set = {2, 3, 5, 7}. The original median = 4.

B. New number = 5; New set = {2, 3, 5, 5, 7}. New median = 5.

C. New number = \(\sqrt{29}\); New set = 2, 3, 5, \(\sqrt{29}\), 7}. New median = 5.

D. New number = 7.7; New set = {2, 3, 5, 7, 7.7}. New median = 5.

E. New number = \(\frac{49}{4}\); New set = {2, 3, 5, 7, 49/4}. New median = 5.