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# M22-36

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Math Expert
Joined: 02 Sep 2009
Posts: 42305

Kudos [?]: 133072 [0], given: 12403

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16 Sep 2014, 01:17
Expert's post
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Difficulty:

45% (medium)

Question Stats:

64% (00:54) correct 36% (02:10) wrong based on 11 sessions

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Circles $$X$$ and $$Y$$ are concentric. If the radius of circle $$X$$ is three times that of circle $$Y$$, what is the probability that a point selected inside circle $$X$$ at random will be outside circle $$Y$$?

A. $$\frac{1}{3}$$
B. $$\frac{\pi}{3}$$
C. $$\frac{\pi}{2}$$
D. $$\frac{5}{6}$$
E. $$\frac{8}{9}$$
[Reveal] Spoiler: OA

_________________

Kudos [?]: 133072 [0], given: 12403

Math Expert
Joined: 02 Sep 2009
Posts: 42305

Kudos [?]: 133072 [0], given: 12403

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16 Sep 2014, 01:17
Official Solution:

Circles $$X$$ and $$Y$$ are concentric. If the radius of circle $$X$$ is three times that of circle $$Y$$, what is the probability that a point selected inside circle $$X$$ at random will be outside circle $$Y$$?

A. $$\frac{1}{3}$$
B. $$\frac{\pi}{3}$$
C. $$\frac{\pi}{2}$$
D. $$\frac{5}{6}$$
E. $$\frac{8}{9}$$

We have to find the ratio of the area of the ring around the small circle to the area of the big circle. If $$y$$ is the radius of the smaller circle, then the area of the bigger circle is $$\pi(3y)^2 = 9 \pi y^2$$. The area of the ring $$= \pi(3y)^2 - \pi(y)^2 = 8 \pi y^2$$. The ratio $$= \frac{8}{9}$$.

_________________

Kudos [?]: 133072 [0], given: 12403

Senior Manager
Status: Math is psycho-logical
Joined: 07 Apr 2014
Posts: 437

Kudos [?]: 141 [1], given: 169

Location: Netherlands
GMAT Date: 02-11-2015
WE: Psychology and Counseling (Other)

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21 Jan 2015, 06:49
1
KUDOS
Hey,

Great that we saw how you do it using the actual variables.
However, I just used values.

For the radius of X = 6
For the radius of Y = 2

Then the area for X = 36π
and the area for Y = 4π

32/36 = 8/9.

Kudos [?]: 141 [1], given: 169

Intern
Joined: 02 Aug 2017
Posts: 6

Kudos [?]: 1 [0], given: 2

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26 Oct 2017, 15:20
I think the easiest way for me was:
$$\frac{πr^2}{π3r^2}$$

Use values Y=1, X=3Y=3

$$1^2 = 1, 3^2=9$$, 1/9 chance it is inside the circle, or 8/9 chance it is outside.

Kudos [?]: 1 [0], given: 2

Re: M22-36   [#permalink] 26 Oct 2017, 15:20
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# M22-36

Moderators: Bunuel, chetan2u

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