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M23-10

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M23-10  [#permalink]

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New post 16 Sep 2014, 01:18
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

84% (00:43) correct 16% (00:45) wrong based on 182 sessions

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Math Expert
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Re M23-10  [#permalink]

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New post 16 Sep 2014, 01:18
Official Solution:

There are 48 roses in a garden. Each of them is either black, red, or white. If the ratio of the number of red roses to the number of white roses is 21:4, how many black roses are there in the garden?

A. 4
B. 6
C. 21
D. 23
E. the data is not sufficient to answer the question

The number of red roses must be a multiple of 21. It cannot be 42 or larger because this would mean that the number of white roses is 8 or larger and the total number of roses is 50 or larger. Because there are only 48 roses in the garden, the number of red roses is 21 and the number of white roses is 4. The number of black roses \(= 48 - 21 - 4 = 23\).

Answer: D
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Re: M23-10  [#permalink]

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New post 30 Sep 2017, 23:42
This is a high quality question.
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M23-10  [#permalink]

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New post 01 Oct 2017, 00:42
1
Bunuel wrote:
There are 48 roses in a garden. Each of them is either black, red, or white. If the ratio of the number of red roses to the number of white roses is 21:4, how many black roses are there in the garden?

A. 4
B. 6
C. 21
D. 23
E. the data is not sufficient to answer the question


let the red and white roses be \(21x\) & \(4x\)

Hence Black rose \(= 48-(21x+4x) = 48-25x\)

Now \(x=1\), because at \(x=2\), no of black roses will be negative which is not possible

Hence no of black rose \(= 48-25=23\)

Option \(D\)
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Re: M23-10  [#permalink]

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New post 27 Feb 2018, 08:13
Is this so called 700+ Question?
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Re: M23-10  [#permalink]

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New post 27 Feb 2018, 10:15
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Re: M23-10   [#permalink] 27 Feb 2018, 10:15
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