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# M23-20

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Math Expert
Joined: 02 Sep 2009
Posts: 44586

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16 Sep 2014, 01:19
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Difficulty:

25% (medium)

Question Stats:

81% (01:52) correct 19% (02:04) wrong based on 113 sessions

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If a car had traveled 20 kmh faster than it actually did, the trip would have lasted 30 minutes less. If the car went exactly 60 km, at what speed did it travel?

A. 35 kmh
B. 40 kmh
C. 50 kmh
D. 60 kmh
E. 65 kmh
[Reveal] Spoiler: OA

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Math Expert
Joined: 02 Sep 2009
Posts: 44586

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16 Sep 2014, 01:19
Expert's post
4
This post was
BOOKMARKED
Official Solution:

If a car had traveled 20 kmh faster than it actually did, the trip would have lasted 30 minutes less. If the car went exactly 60 km, at what speed did it travel?

A. 35 kmh
B. 40 kmh
C. 50 kmh
D. 60 kmh
E. 65 kmh

Solve the equation $$\frac{60}{x} = \frac{60}{x + 20} + 0.5$$. Backsolve: $$\frac{60}{40} = \frac{60}{40 + 20} + 0.5$$.

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Joined: 17 May 2016
Posts: 31
GMAT 1: 740 Q46 V46

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19 Dec 2016, 10:08
Hi,

Is it possible to calculate it algebraically ?

I get stuck with two unknown, even if I know that is quicker to back solve, I do not understand why it is not solvable ?

Math Expert
Joined: 02 Sep 2009
Posts: 44586

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19 Dec 2016, 10:18
nickimonckom wrote:
Hi,

Is it possible to calculate it algebraically ?

I get stuck with two unknown, even if I know that is quicker to back solve, I do not understand why it is not solvable ?

Which two unknowns are you talking about? There is only one unknown in the equation above. If you simplify $$\frac{60}{x} = \frac{60}{x + 20} + 0.5$$ you'll get quadratic equation which will give two values of x: -60 (discard) and 40.
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Intern
Joined: 17 May 2016
Posts: 31
GMAT 1: 740 Q46 V46

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20 Dec 2016, 02:53
I mean that if I set up the table, I get the following :

FIRST MOVE : $$r*(t+\frac{1}{2}) = 60$$
2ND MOVE : $$(r+20)*t = 60$$

Then, since they are equal :
$$r*(t+\frac{1}{2}) = (r+20)*t$$
$$rt + \frac{r}{2} = rt + 20t$$
$$r = 40t$$

Then I have a problem with the unit, I know that 40 is the good value but I am not supposed to express a rate and a time, only a rate.

Manager
Joined: 23 Jan 2016
Posts: 218
Location: India
GPA: 3.2

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06 Apr 2017, 22:33
Could you please share some links to questions similar to this? Thank you.
Math Expert
Joined: 02 Sep 2009
Posts: 44586

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07 Apr 2017, 00:29
OreoShake wrote:
Could you please share some links to questions similar to this? Thank you.

Check Distance/Rate problems from our Questions' Bank: https://gmatclub.com/forum/viewforumtags.php

Hope it helps.
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Manager
Joined: 28 Dec 2016
Posts: 86

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09 Apr 2018, 12:05
For those of you wanting to set up an equation and solve it w/o plugging in, I can chime in to help.
Since traveling at 20kmh faster saves 1/2 hour, we can say that:
60/R - 60/(R+20) = 1/2, which is basically saying:
(Time at Reg Speed) - (Time +20kmh faster) = (30 mins)

Solving, we get:
(R+60)(R-40)=0
R= -60, 40

Rate can not be negative, therefore, 40 is the winner.
Re: M23-20   [#permalink] 09 Apr 2018, 12:05
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# M23-20

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