|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
16 Sep 2014, 01:19
Kudos
Bookmarks
If \(x\), \(y\), and \(z\) are positive integers, is \(x*y*z\) even?
(1) \(x - y\) is odd.
(2) \(y*z + x\) is odd.
(1) \(x - y\) is odd.
(2) \(y*z + x\) is odd.
16 Sep 2014, 01:20
Kudos
Bookmarks
Official Solution:
If \(x\), \(y\), and \(z\) are positive integers, is \(x*y*z\) even?
Firstly, let's note that the product of integers will be even if at least one of them is even.
(1) \(x - y\) is odd.
For the difference of two integers to be odd, one of them must be odd and the other even. Thus, either \(x\) or \(y\) is even. This ensures that \(x*y*z\) is even. Sufficient.
(2) \(y*z + x\) is odd.
For the sum of two integers, \(y*z\) and \(x\), to be odd, one of them must be odd and the other even. Thus, either \(yz\) or \(x\) is even. This ensures that \(x*y*z\) is even. Sufficient.
Answer: D
If \(x\), \(y\), and \(z\) are positive integers, is \(x*y*z\) even?
Firstly, let's note that the product of integers will be even if at least one of them is even.
(1) \(x - y\) is odd.
For the difference of two integers to be odd, one of them must be odd and the other even. Thus, either \(x\) or \(y\) is even. This ensures that \(x*y*z\) is even. Sufficient.
(2) \(y*z + x\) is odd.
For the sum of two integers, \(y*z\) and \(x\), to be odd, one of them must be odd and the other even. Thus, either \(yz\) or \(x\) is even. This ensures that \(x*y*z\) is even. Sufficient.
Answer: D
23 Oct 2023, 02:46
Kudos
Bookmarks
I've revised the question and solution, incorporating additional details for improved clarity. I trust this makes it more comprehensible.
