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M23-31

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M23-31  [#permalink]

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New post 16 Sep 2014, 00:19
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

80% (01:02) correct 20% (01:11) wrong based on 116 sessions

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Re M23-31  [#permalink]

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New post 16 Sep 2014, 00:20
Official Solution:


Statement (1) by itself is sufficient. From S1 it follows that \(X\) and \(Y\) cannot both be odd or even. One of them must be even and the other must be odd. This information is enough to state that \(X*Y*Z\) is even.

Statement (2) by itself is sufficient. From S2 it follows that either \(Y*Z\) or \(X\) is even. This information is enough to state that \(X*Y*Z\) is even.


Answer: D
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Re: M23-31  [#permalink]

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New post 28 Mar 2018, 06:26
+1 for option D.
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Re: M23-31  [#permalink]

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New post 28 Mar 2018, 08:40
Question is basically asking us X, Y, Z - do we have one variable that is even?

If ANY of these variables are even, then the product of all three numbers are even
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Re: M23-31  [#permalink]

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New post 28 Mar 2018, 19:10
To determine whether the product X * Y * Z is even is to specify whether any one of those variables is even

1. X - Y is odd;
(even - odd = odd)
(odd - even = odd)
either X or Y is even --> Sufficient

2. Y * Z + X is odd;
(even + odd = odd)
(odd + even = odd)
either Y * Z or X is even --> Sufficient
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Re: M23-31 &nbs [#permalink] 28 Mar 2018, 19:10
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M23-31

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