|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
16 Sep 2014, 01:21
Kudos
Bookmarks
A basket contains 13 fruits: 5 apples and 8 pears. What is the probability that two fruits drawn at random from the basket without replacement will both be pears?
A. \(\frac{9}{28}\)
B. \(\frac{1}{3}\)
C. \(\frac{14}{39}\)
D. \(\frac{15}{28}\)
E. \(\frac{8}{13}\)
A. \(\frac{9}{28}\)
B. \(\frac{1}{3}\)
C. \(\frac{14}{39}\)
D. \(\frac{15}{28}\)
E. \(\frac{8}{13}\)
16 Sep 2014, 01:21
Kudos
Bookmarks
Official Solution:
A basket contains 13 fruits: 5 apples and 8 pears. What is the probability that two fruits drawn at random from the basket without replacement will both be pears?
A. \(\frac{9}{28}\)
B. \(\frac{1}{3}\)
C. \(\frac{14}{39}\)
D. \(\frac{15}{28}\)
E. \(\frac{8}{13}\)
The probability that both fruits are pears is equal to the probability that the first fruit is a pear multiplied by the probability that the second fruit is a pear. This is calculated as \(= \frac{8}{13}*\frac{7}{12} = \frac{14}{39}\).
Answer: C
A basket contains 13 fruits: 5 apples and 8 pears. What is the probability that two fruits drawn at random from the basket without replacement will both be pears?
A. \(\frac{9}{28}\)
B. \(\frac{1}{3}\)
C. \(\frac{14}{39}\)
D. \(\frac{15}{28}\)
E. \(\frac{8}{13}\)
The probability that both fruits are pears is equal to the probability that the first fruit is a pear multiplied by the probability that the second fruit is a pear. This is calculated as \(= \frac{8}{13}*\frac{7}{12} = \frac{14}{39}\).
Answer: C
30 Jun 2017, 23:22
Kudos
Bookmarks
As Bunuel sir explained, it is a pick and not replace method. One of the fastest method to solve this kind of easy question.
People who are familiar with combinations can also use this method.
(2C8/2C13)= 28/78 = 14 / 39.
People who are familiar with combinations can also use this method.
(2C8/2C13)= 28/78 = 14 / 39.
