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M24-26

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V
Joined: 02 Sep 2009
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M24-26  [#permalink]

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New post 16 Sep 2014, 01:22
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

66% (00:24) correct 34% (00:37) wrong based on 94 sessions

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Math Expert
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Joined: 02 Sep 2009
Posts: 47918
Re M24-26  [#permalink]

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New post 16 Sep 2014, 01:22
Official Solution:


20 throws of a die produces following results:

Image

What is the median score of this series of throws?


A. 2.50
B. 3.00
C. 3.35
D. 3.50
E. 4.00


The median of a set with even number of terms is the average of two middle terms when arranged in ascending/descending order. So, the median of our set of 20 terms is the average of 10th and 11th terms when arranged in ascending/descending order:

1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4, 5, 5, 6, 6, 6, 6.

So, the median is \(\frac{3+3}{2}=3\).


Answer: B
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Re: M24-26  [#permalink]

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New post 11 May 2018, 05:43
if we calculate number of occurences =4+3+5+2+2+4=20
So for even number of values median =sum of middle values /2

MIddle values here =10th term and 11th term

While calculating median we need to sort values in ascending order
so 4 values of Score 1
3 values of Score 2

5 values of Score 3

10th and 11th term values score are 3

So median =(3+3)/2=3
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Re: M24-26  [#permalink]

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New post 11 May 2018, 08:27
total numbers in the set =20 (20 throws given )
median of 20 numbers = mean of 10th and 11th term

now looking at the table
1 occurs 4 times
2 occurs 3 times
3 occurs 5 times
------------------
12 numbers of set covered we need 10 and 11 so 3 is 10th and 11th term

mean =(3+3)/2 = 3

B is the answer
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Re: M24-26  [#permalink]

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New post 11 May 2018, 22:02
+1 for option B. Write down the numbers and the mean comes out to 3.
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Re: M24-26 &nbs [#permalink] 11 May 2018, 22:02
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