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M24-28

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M24-28  [#permalink]

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New post 16 Sep 2014, 00:22
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A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

71% (01:07) correct 29% (01:00) wrong based on 49 sessions

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New post 16 Sep 2014, 00:22
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Re: M24-28  [#permalink]

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New post 03 Nov 2015, 06:01
Bunuel wrote:
Official Solution:

S1 + S2 is not sufficient. Consider \(x = 3\), \(y = 4\), \(z = 5\) (the answer is YES) and \(x = 5\), \(y = 6\), \(z = 7\) (the answer is NO).

Answer: E


Hi Bunuel,

345 is not divisible by 12 right?

I think C is OK.
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New post 03 Nov 2015, 08:24
Mickjagger wrote:
Bunuel wrote:
Official Solution:

S1 + S2 is not sufficient. Consider \(x = 3\), \(y = 4\), \(z = 5\) (the answer is YES) and \(x = 5\), \(y = 6\), \(z = 7\) (the answer is NO).

Answer: E


Hi Bunuel,

345 is not divisible by 12 right?

I think C is OK.


xyz means x*y*z.
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New post 04 Nov 2015, 03:43
Bunuel

I have a general question that popped up in my mind because of this question.

In this case, is it safe to assume that 'x' will always be the smallest integer when we say that x,y,z are consecutive integers (Statement 1) ?
Or, can we assume 'z' or 'y' the smallest too ?

Thinking in this way for statement 2, can we take, y=1, x=2, and z=3 ? (x and z are prime numbers)
Using statement 2, we get the value of xyz/12 NOT EQUAL to an integer and makes option C as the final answer to the question.

Please assist.
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New post 04 Nov 2015, 04:20
puneetgangrade wrote:
Bunuel

I have a general question that popped up in my mind because of this question.

In this case, is it safe to assume that 'x' will always be the smallest integer when we say that x,y,z are consecutive integers (Statement 1) ?
Or, can we assume 'z' or 'y' the smallest too ?

Thinking in this way for statement 2, can we take, y=1, x=2, and z=3 ? (x and z are prime numbers)
Using statement 2, we get the value of xyz/12 NOT EQUAL to an integer and makes option C as the final answer to the question.

Please assist.


No, you cannot assume that x<y<z if you are not explicitly told that. But the answer is not C because no matter whether x<y<z or not, you can get a NO as well as an YES answer to the question asked (check examples in the solution).
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New post 04 Nov 2015, 05:15
Ok, Bunuel. Yes, I understand that C cannot be the answer.
Thanks a lot for the prompt reply.
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New post 25 Aug 2018, 05:44
Hi Bunuel,
can we rewrite the stem as is xyz=12* int=int?
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New post 26 Aug 2018, 03:32
Hi bunuel,
Sorry that i wqs not specific in asking my doubt. As 12 is an integer, whats wrong in rephrasing the question as follows: Is xyz=12*int=int i.e is xyz an integer?

By doing so Answer would be A.Could u explain why the question should not be rephrased this way?

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New post 26 Aug 2018, 03:35
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Satya91 wrote:
Hi bunuel,
Sorry that i wqs not specific in asking my doubt. As 12 is an integer, whats wrong in rephrasing the question as follows: Is xyz=12*int=int i.e is xyz an integer?

By doing so Answer would be A.Could u explain why the question should not be rephrased this way?

Posted from my mobile device


xyz could be an integer and not a multiple of 12. So, the question should be rephrased as written in my previous post.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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New post 26 Aug 2018, 03:58
Yeah got it. Thank you bunuel.

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M24-28 &nbs [#permalink] 26 Aug 2018, 03:58
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