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M25-37

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M25-37  [#permalink]

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New post 16 Sep 2014, 00:24
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A
B
C
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E

Difficulty:

  5% (low)

Question Stats:

93% (00:49) correct 7% (01:16) wrong based on 305 sessions

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A cylindrical tank has a base radius of 1 meters and a height equal to 2 meters. The tank is half full of water. If all the water from that tank is poured into another cylindrical tank with the base radius equal to 2 meters and a height of 1 meters, what percent of this new tank will be filled with water?

A. 20%
B. 25%
C. 32%
D. 35%
E. 40%

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Re M25-37  [#permalink]

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New post 16 Sep 2014, 00:24
1
Official Solution:

A cylindrical tank has a base radius of 1 meters and a height equal to 2 meters. The tank is half full of water. If all the water from that tank is poured into another cylindrical tank with the base radius equal to 2 meters and a height of 1 meters, what percent of this new tank will be filled with water?

A. 20%
B. 25%
C. 32%
D. 35%
E. 40%


The volume of a cylinder is \(\pi*r^2*h\).

The volume of tank #1 is \(\pi*1^2*2=2 \pi\). Since, the tank is half full, then the volume of water in it is \(\frac{2 \pi}{2}=\pi\).

The volume of tank #2 is \(\pi*2^2*1=4 \pi\).

Percent of water in tank #2 is \(\frac{\pi}{4 \pi}*100=25%\).


Answer: B
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: M25-37  [#permalink]

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New post 18 Jul 2018, 19:19
Bunuel wrote:
A cylindrical tank has a base radius of 1 meters and a height equal to 2 meters. The tank is half full of water. If all the water from that tank is poured into another cylindrical tank with the base radius equal to 2 meters and a height of 1 meters, what percent of this new tank will be filled with water?

A. 20%
B. 25%
C. 32%
D. 35%
E. 40%


This can be solved by simple application of the formula of the Volume of the Cylinder = πr^2h

Volume of water in Tank 1= π*1^2*2/2 (since it is half full)= π
Volume of Tank 2= π*2^2*1=4 π
Now Percent of 2nd tank filled = (π/4π)*100 = 25%
Hence B is the answer.
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Re: M25-37 &nbs [#permalink] 18 Jul 2018, 19:19
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