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16 Sep 2014, 01:28
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16 Sep 2014, 01:28
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Official Solution:
Is \(x = 0\)?
(1) \(xy = x\).
Rearrange and factor out \(x\) to get \(x(y - 1) = 0\). This implies that either \(x = 0\) (and \(y\) can take any value) OR \(y = 1\) (and \(x\) can take any value). Not sufficient.
(2) \(x+y=x\).
This statement implies that \(y = 0\). However, it is not sufficient to answer whether \(x = 0\).
(1) + (2) From statement (2), we know that \(y = 0 \neq 1\). Therefore, according to statement (1), \(x = 0\). Sufficient.
Answer: C
Is \(x = 0\)?
(1) \(xy = x\).
Rearrange and factor out \(x\) to get \(x(y - 1) = 0\). This implies that either \(x = 0\) (and \(y\) can take any value) OR \(y = 1\) (and \(x\) can take any value). Not sufficient.
(2) \(x+y=x\).
This statement implies that \(y = 0\). However, it is not sufficient to answer whether \(x = 0\).
(1) + (2) From statement (2), we know that \(y = 0 \neq 1\). Therefore, according to statement (1), \(x = 0\). Sufficient.
Answer: C
17 Oct 2015, 14:04
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I think this is a high-quality question and I agree with explanation. I'm confused as to why I cannot divide statement 1 by zero to get to y=1. I know that x=0 is clearly a possibility i just don't get why I cannot divide both sides by X.
