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Bunuel
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Bunuel
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bigzoo
could help me please what does it mean: "The length of the median BD" ... first I thought it is the midpoint of BC, but it is not ... and since english is not my mother tounge I do not know what it means

The median of a triangle is a line from a vertex to the midpoint of the opposite side. Check for more HERE.
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Please correct my reasoning. I do not understand why A is not correct. Let's name each side of our equilateral triangle "x." AB=BC=AC=x. Since we are told BD is a median, it means AD=DC=x/2. In an equilateral triangle, a line drawn from one of the vertices to the midpoint of the opposite line will form a 90 degree angle. So we would have two equal triangles, AB-BD-DA and CB-BD-DC that each have one side, BD, length 12, one side, DC or DA, length x/2, and one side, BC or BA, length x. Since these are right triangles, (x/2)^2+12^2=x^2. We have an equation with one unknown. Why is this not sufficient? Bunuel can you help?
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Please correct my reasoning. I do not understand why A is not correct. Let's name each side of our equilateral triangle "x." AB=BC=AC=x. Since we are told BD is a median, it means AD=DC=x/2. In an equilateral triangle, a line drawn from one of the vertices to the midpoint of the opposite line will form a 90 degree angle. So we would have two equal triangles, AB-BD-DA and CB-BD-DC that each have one side, BD, length 12, one side, DC or DA, length x/2, and one side, BC or BA, length x. Since these are right triangles, (x/2)^2+12^2=x^2. We have an equation with one unknown. Why is this not sufficient? Bunuel can you help?


(1) says that ABC is isosceles, not equilateral.
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Hi Bunuel,

Could you please elaborate (as in how does it come about) on the geometrical property mentioned for the sufficiency of Statement 2 : "Important property: median from right angle is half of the hypotenuse"?

It would just make it easier to remember.

Thanks.
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Sriparnacj I had the same thought. Draw a line from midpoint D to line BC on the triangle, and call the point "E" on line BC. You can then prove that triangle CDE and BDE are identical. Or, you could prove that BDE and ABC are congruent.

Annoyingly I can't post URLs but I would google the triangle midsegment theorem for more info. Hope this helps
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Duplicate of M04-24. Unpublished.
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