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26 May 2017, 04:48
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How many factors of 2,310 are odd numbers greater than 1?
A. 7
B. 8
C. 11
D. 15
E. 16
A. 7
B. 8
C. 11
D. 15
E. 16
26 May 2017, 04:49
Kudos
Bookmarks
Official Solution:
How many factors of 2,310 are odd numbers greater than 1?
A. 7
B. 8
C. 11
D. 15
E. 16
\(2,310 = (2)(3)(5)(7)(11)\), and the question is about factors that are odd numbers, so if you take away 2, you get \((3)(5)(7)(11)\). The number of factors becomes \((3)(5)(7)(11) = (3^{1})(5^{1})(7^{1})(11^{1})to(1+1)(1+1)(1+1)(1+1) = 16\). However, the question is about odd factors greater than 1, so you exclude 1, and the answer is \(16 - 1 = 15\). Therefore, D is the answer.
Answer: D
How many factors of 2,310 are odd numbers greater than 1?
A. 7
B. 8
C. 11
D. 15
E. 16
\(2,310 = (2)(3)(5)(7)(11)\), and the question is about factors that are odd numbers, so if you take away 2, you get \((3)(5)(7)(11)\). The number of factors becomes \((3)(5)(7)(11) = (3^{1})(5^{1})(7^{1})(11^{1})to(1+1)(1+1)(1+1)(1+1) = 16\). However, the question is about odd factors greater than 1, so you exclude 1, and the answer is \(16 - 1 = 15\). Therefore, D is the answer.
Answer: D
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