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In Episode 4 of our GMAT Ninja CR series, we tackle the most intimidating CR question type: Boldface & "Legalese" questions. If you've ever stared at an answer choice that reads, "The first is a consideration introduced to counter a position that...- May 14
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27 Apr 2025, 04:41
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I don’t quite agree with the solution. if we use _ approach to solve this question then total number of four digit numbers that can be formed is 9x9x8x7. 9 for thousand place because 0 not allowed. 9 for hundred place because 0 allowed but thousand digit not allowed and so on. thus total 4536 numbers can be formed. Now divide that by 4! to get the numbers which are in ascending order. 4536/4! = 189.
27 Apr 2025, 09:07
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Shivam2024
Your method is wrong because when you do 9*9*8*7, you are counting all four-digit numbers with different digits, including numbers where 0 is one of the digits. But we already established that 0 cannot appear at all.
Also, when you divide by 4!, you are still including numbers where 0 is the first digit, which are not acceptable.
The original solution using 9C4 = 126 is correct. I suggest you review it and the full discussion more carefully.
27 Apr 2025, 10:32
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Okay I get it, maybe I missed the emphasis of the numbers being in ascending order. Thus 0 can not be part of the selection because it is the smallest integer from 0 - 9 as such no integer can precede it. Also if it acquires the thousands place the resultant number will ultimately be a three digit number. Can I use the logic (9x9x8x7)/4! had the question asked descending order?
Bunuel
