Official Solution:Is the perimeter of a rectangle more than 60 cm ? (1) The area of the rectangle is 226 cm^2.
Given \(ab = 226\).
Now,
for rectangles with a fixed area, a square has the minimum perimeter. So, the minimum perimeter will occur when \(a=b\). In this case, we'd have \(a^2=226\).
\(a=15.something\) and thus the perimeter is \(4*15.something=60.something>60\). As even the minimum possible perimeter is more than 60 cm, then the actual perimeter, whatever it is, is also more than 60 cm. Sufficient.
(2) The length of a diagonal of the rectangle is 30 cm.
The diagonal, the length and the width of a rectangle form a triangle and in a triangle the length of any side must be smaller than the sum of the other two sides. So, \(a+b>30\) and thus \(perimeter=2(a + b) > 60\) Sufficient.
Answer: D