Official Solution:If \(\frac{0.0019}{-x} > 2\), then which of the following could be the value of \(x\) ? A. \(-10^{-1}\)
B. \(-10^{-2}\)
C. \(-10^{-3}\)
D. \(-10^{-4}\)
E. \(10^4\)
First of all, notice that \(-10^{-1} < -10^{-2} < -10^{-3} < -10^{-4} < 10^4\)
Also, notice that since \(\frac{0.0019}{-x}\) is positive, then \(x\) must be a negative number. We can rule out option E.
Multiply \(\frac{0.0019}{-x} > 2\) by \(x\) and flip the sign because we are multiplying by a negative number: \(-0.0019 < 2x\);
\(x > -0.00095\);
\(x > (-10^{-3})*0.95\)
Since \((-10^{-3})*0.95 > -10^{-3}\), then \(x>(-10^{-3})*0.95 > -10^{-3}\).
\(x\) can only be \(-10^{-4}\) from the options.
Answer: D