Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 1308:30 AM PDT
-09:30 AM PDT
In Episode 4 of our GMAT Ninja CR series, we tackle the most intimidating CR question type: Boldface & "Legalese" questions. If you've ever stared at an answer choice that reads, "The first is a consideration introduced to counter a position that...
May 1212:00 PM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products.- May 14
08:30 AM PDT
-09:30 AM PDT
Most GMAT test-takers are intimidated by the hardest GMAT Verbal questions. In this session, Target Test Prep GMAT instructor Erika Tyler-John, a 100th percentile GMAT scorer, will show you how top scorers break down challenging Verbal questions.. - Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
27 Apr 2023, 09:53
Kudos
Bookmarks
If \(s - \frac{1}{s} < \frac{1}{t} - t\), then is \(s > t\)?
(1) \(s > 1\)
(2) \(t > 0\)
(1) \(s > 1\)
(2) \(t > 0\)
27 Apr 2023, 09:53
Kudos
Bookmarks
Official Solution:
If \(s - \frac{1}{s} < \frac{1}{t} - t\), then is \(s > t\)?
First, let's rewrite the inequality as \(s + t < \frac{1}{s} + \frac{1}{t}\).
(1) \(s > 1\)
If \(1 < s \leq t\) were true, then \(s + t\) would be the sum of two numbers greater than 1, hence more than 2. On the other hand, \(\frac{1}{s} + \frac{1}{t}\) would be the sum of two numbers less than 1, which would be a number less than 2. Therefore, if \(s < t\) were true, \(1 < s \leq t\) would be greater than \(\frac{1}{s} + \frac{1}{t}\), contradicting the given inequality. Consequently, \(1 < s \leq t\) is not possible, and thus, \(s > t\). Sufficient.
(2) \(t > 0\)
Without any information on \(s\), this statement is not sufficient. For example, consider \(s = -2\) and \(t = 1\) for a NO answer, and \(s = 1\) and \(t = \frac{1}{2}\) for a YES answer.
Answer: A
If \(s - \frac{1}{s} < \frac{1}{t} - t\), then is \(s > t\)?
First, let's rewrite the inequality as \(s + t < \frac{1}{s} + \frac{1}{t}\).
(1) \(s > 1\)
If \(1 < s \leq t\) were true, then \(s + t\) would be the sum of two numbers greater than 1, hence more than 2. On the other hand, \(\frac{1}{s} + \frac{1}{t}\) would be the sum of two numbers less than 1, which would be a number less than 2. Therefore, if \(s < t\) were true, \(1 < s \leq t\) would be greater than \(\frac{1}{s} + \frac{1}{t}\), contradicting the given inequality. Consequently, \(1 < s \leq t\) is not possible, and thus, \(s > t\). Sufficient.
(2) \(t > 0\)
Without any information on \(s\), this statement is not sufficient. For example, consider \(s = -2\) and \(t = 1\) for a NO answer, and \(s = 1\) and \(t = \frac{1}{2}\) for a YES answer.
Answer: A
