which is greater then -0.1 but less then 0... can you explain a bit more?
MBAToronto2024
KarishmaB I did the following: the x cannot be less than -1. That's why I selected A. Any advice on how to approach this kind of questions?
Yes, we need to understand the number line for this. Let's convert it to exponents because those are easier to understand.
\(x = - ^{200}\sqrt{0.2}\)
\(-x = ^{200}\sqrt{0.2}\)
\(x^{200} = 0.2\)
x is negative. But let's evaluate its absolute value only for the time being. For now x just means absolute value of x. We will add a minus sign to it later.
When a number greater than 1 is multiplied by itself it becomes larger and larger so x cannot be more than 1.
When a number in the range 0 to 1 is multiplied with itself, it becomes smaller and smaller
(0.9)^2 = 0.81
(0.9)^3 = 0.729
(0.9)^4 = 0.6... (something)
(0.9)^5 = 0.5...
Falling rapidly.
When x is raised to power 200, we get 0.2. So x must be between 0 and 1 but very very close to 1. You see how quickly 0.9 is dropping and will become 0.2 very soon? Hence x absolute value must be greater than 0.9 but must remain less than 1. Hence x will lie between -0.9 and -1. It will be something like -0.9999...
Answer (B)
I have discussed these relations on the number line in detail in my Exponents and Roots study module.