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Bunuel
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Josvit
a*y+b=c

a= 1, b=2, c=3; y=1
a=2, b=3, c=7; y=2
a=3, b=4, c=13; y=3

.... and so on.

Because the question is not asking about y in terms of a,b or c. Perhaps, some additional details might be good for this. thanks.­
­We are told that a, b, and c are constants, meaning that each has one fixed value.­
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Is there no possibility that c=b? In this case, y=0, otherwise with all constants>0, y would have a fixed solution. If we do consider the first case too, then there would be 2 possible values of y
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Is there no possibility that c=b? In this case, y=0, otherwise with all constants>0, y would have a fixed solution. If we do consider the first case too, then there would be 2 possible values of y

c can be equal to b; however, this changes nothing. Again, a, b, and c are constants, meaning that each has a single fixed value. Therefore, regardless of their specific values, there is exactly one possible value for y. If you claim that there will be two values of y possible, then please provide specific values for a, b, and c such that, when substituted into a * y + b = c, the equation yields two distinct values for y.
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Thanks for the detailed explanation, got it now
Bunuel
prabhatshahi9
Is there no possibility that c=b? In this case, y=0, otherwise with all constants>0, y would have a fixed solution. If we do consider the first case too, then there would be 2 possible values of y

c can be equal to b; however, this changes nothing. Again, a, b, and c are constants, meaning that each has a single fixed value. Therefore, regardless of their specific values, there is exactly one possible value for y. If you claim that there will be two values of y possible, then please provide specific values for a, b, and c such that, when substituted into a * y + b = c, the equation yields two distinct values for y.
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I came across a similar question which just had "different constants" instead of "positive constants" in the question.
That question had the answer of Cannot be Determined.

How much of a difference does this make can you please explain? Didn't understand this quite well.

Thanks
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Bunuel
Official Solution:

If \(a\), \(b\), and \(c\) are positive constants, how many different numbers \(y\) are there such that \(a*y + b = c\)?

A. 0
B. 1
C. 2
D. Infinitely many
E. Cannot be determined from the given information­


Since \(a\) is nonzero, then \(y = \frac{c - b}{a} = \frac{c - b}{nonzero \ number}\).

As a result, regardless of the value of \(c - b\), the equation \(a*y = c - b\) will always have only one solution, given by: \(y =\frac{c - b}{nonzero \ number}\).


Answer: B
I came across a similar question which just had "different constants" instead of "positive constants" in the question.
That question had the answer of Cannot be Determined.

How much of a difference does this make can you please explain? Didn't understand this quite well.

Thanks

Positive constants means constants are positive. However, in general, they can be equal.

Different constants just means they are not equal to each other, but any of them could be negative, zero, or positive.
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Thanks got it!
Bunuel
SaiJ1011

Bunuel
Official Solution:

If \(a\), \(b\), and \(c\) are positive constants, how many different numbers \(y\) are there such that \(a*y + b = c\)?

A. 0
B. 1
C. 2
D. Infinitely many
E. Cannot be determined from the given information­


Since \(a\) is nonzero, then \(y = \frac{c - b}{a} = \frac{c - b}{nonzero \ number}\).

As a result, regardless of the value of \(c - b\), the equation \(a*y = c - b\) will always have only one solution, given by: \(y =\frac{c - b}{nonzero \ number}\).


Answer: B
I came across a similar question which just had "different constants" instead of "positive constants" in the question.
That question had the answer of Cannot be Determined.

How much of a difference does this make can you please explain? Didn't understand this quite well.

Thanks

Positive constants means constants are positive. However, in general, they can be equal.

Different constants just means they are not equal to each other, but any of them could be negative, zero, or positive.
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Can someone explain me this.

if a =1 b = 2 c = 10 Y = 10-2/1 = 8
if a = 2 b = 3 c = 15 Y = 15-3/2 = 4

different values are possible for right? how 1 value is the solution here? Y = (c-b)/a
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pavanhra
Can someone explain me this.

if a =1 b = 2 c = 10 Y = 10-2/1 = 8
if a = 2 b = 3 c = 15 Y = 15-3/2 = 4

different values are possible for right? how 1 value is the solution here? Y = (c-b)/a

a, b, and c are constants, meaning they have fixed values. Once these values are set, the equation a*y + b = c has only one solution for y, given by y = (c - b)/a. The value of y changes if a, b, or c changes, but for any fixed set, there is only one y. So the answer is B: 1.
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I did not quite understand the solution. they asked different numbers not ..... number of solutions
and through combinations of a,b,c we can get as many different numbers as we want
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needforspeed112
I did not quite understand the solution. they asked different numbers not ..... number of solutions
and through combinations of a,b,c we can get as many different numbers as we want

Please check again:

If \(a\), \(b\), and \(c\) are positive constants, how many different numbers \(y\) are there such that \(a*y + b = c\)?
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