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Two pumps, X and Y, can fill a tank in 10 and 20 minutes, respectively. Both are turned on simultaneously, but after 5 minutes, pump X is turned off. How much additional time will pump Y take to fill the tank completely?
A. 4 minutes
B. 5 minutes
C. 6 minutes
D. 7 minutes
E. 8 minutes
A. 4 minutes
B. 5 minutes
C. 6 minutes
D. 7 minutes
E. 8 minutes
11 Mar 2026, 03:23
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Official Solution:
Two pumps, X and Y, can fill a tank in 10 and 20 minutes, respectively. Both are turned on simultaneously, but after 5 minutes, pump X is turned off. How much additional time will pump Y take to fill the tank completely?
A. 4 minutes
B. 5 minutes
C. 6 minutes
D. 7 minutes
E. 8 minutes
Pump X rate \(= \frac{1}{10}\) tank per minute.
Pump Y rate \(= \frac{1}{20}\) tank per minute.
Together rate \(= \frac{1}{10} + \frac{1}{20} = \frac{3}{20}\) tank per minute.
In 5 minutes, filled \(= 5 * \frac{3}{20} = \frac{15}{20} = \frac{3}{4}\) of the tank.
Remaining \(= \frac{1}{4}\) of the tank.
After X is turned off, Y alone fills at \(\frac{1}{20}\) tank per minute.
Time for remaining \(\frac{1}{4}\) of the tank \(= \frac{work}{rate}=\frac{(\frac{1}{4})}{(\frac{1}{20})} = 5\) minutes.
Answer: B
Two pumps, X and Y, can fill a tank in 10 and 20 minutes, respectively. Both are turned on simultaneously, but after 5 minutes, pump X is turned off. How much additional time will pump Y take to fill the tank completely?
A. 4 minutes
B. 5 minutes
C. 6 minutes
D. 7 minutes
E. 8 minutes
Pump X rate \(= \frac{1}{10}\) tank per minute.
Pump Y rate \(= \frac{1}{20}\) tank per minute.
Together rate \(= \frac{1}{10} + \frac{1}{20} = \frac{3}{20}\) tank per minute.
In 5 minutes, filled \(= 5 * \frac{3}{20} = \frac{15}{20} = \frac{3}{4}\) of the tank.
Remaining \(= \frac{1}{4}\) of the tank.
After X is turned off, Y alone fills at \(\frac{1}{20}\) tank per minute.
Time for remaining \(\frac{1}{4}\) of the tank \(= \frac{work}{rate}=\frac{(\frac{1}{4})}{(\frac{1}{20})} = 5\) minutes.
Answer: B
