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26 Apr 2026, 11:00
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A 120-meter-long train is moving at 48 kilometers per hour, while a man is running in the opposite direction on a parallel path at 100 meters per minute. From the moment the front of the train reaches the man until the last carriage passes him, how much time will it take for the train to completely pass the man?
A. 6 seconds
B. 7.5 seconds
C. 8 seconds
D. 9 seconds
E. 10 seconds
A. 6 seconds
B. 7.5 seconds
C. 8 seconds
D. 9 seconds
E. 10 seconds
26 Apr 2026, 11:00
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Official Solution:
A 120-meter-long train is moving at 48 kilometers per hour, while a man is running in the opposite direction on a parallel path at 100 meters per minute. From the moment the front of the train reaches the man until the last carriage passes him, how much time will it take for the train to completely pass the man?
A. 6 seconds
B. 7.5 seconds
C. 8 seconds
D. 9 seconds
E. 10 seconds
The train needs to cover its full length relative to the man, so use relative speed.
Train speed = \(48 * \frac{1000}{60} = 800\) m/min
Relative speed = \(800 + 100 = 900\) m/min
Time = \(\frac{120}{900}\) minutes = \(\frac{2}{15}\) minutes = \(\frac{2}{15} * 60 = 8\) seconds
Answer: C
A 120-meter-long train is moving at 48 kilometers per hour, while a man is running in the opposite direction on a parallel path at 100 meters per minute. From the moment the front of the train reaches the man until the last carriage passes him, how much time will it take for the train to completely pass the man?
A. 6 seconds
B. 7.5 seconds
C. 8 seconds
D. 9 seconds
E. 10 seconds
The train needs to cover its full length relative to the man, so use relative speed.
Train speed = \(48 * \frac{1000}{60} = 800\) m/min
Relative speed = \(800 + 100 = 900\) m/min
Time = \(\frac{120}{900}\) minutes = \(\frac{2}{15}\) minutes = \(\frac{2}{15} * 60 = 8\) seconds
Answer: C
