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21 Jun 2019, 00:21
Kudos
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Let Ra be the rate of Machine A and Rb be the rate of Machine B, and Ta be the time for Machine A to produce 1 widget.
Ra + Rb = 1/3 widget in 1 hour
2Ra + Rb = 1/2 widget in 1 hour
Therefore what is Ta to produce 1 widget? Find Ta
Therefore Rb = 1/3-Ra
Therefore 2Ra + 1/3 - Ra = 1/2
Ra = 1/2 - 1/3
Ra = 1/6 of a widget in 1 hour
Therefore it takes 6 hours for Machine A to produce 1 widget.
Therefore E.
Ra + Rb = 1/3 widget in 1 hour
2Ra + Rb = 1/2 widget in 1 hour
Therefore what is Ta to produce 1 widget? Find Ta
Therefore Rb = 1/3-Ra
Therefore 2Ra + 1/3 - Ra = 1/2
Ra = 1/2 - 1/3
Ra = 1/6 of a widget in 1 hour
Therefore it takes 6 hours for Machine A to produce 1 widget.
Therefore E.
19 Oct 2020, 21:42
Kudos
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(A+B) in 1 hour =1/3 widget
Efficiency: A:B=1:1................1
New Efficiency: A:B=2:1 ............2
(A+B) in 1 hour = 1/2 widget ..........3
From 2 and 3,
1/2=(2+1)
1=6unit
From 1,
A=1*6=6hours....(Ans)
Efficiency: A:B=1:1................1
New Efficiency: A:B=2:1 ............2
(A+B) in 1 hour = 1/2 widget ..........3
From 2 and 3,
1/2=(2+1)
1=6unit
From 1,
A=1*6=6hours....(Ans)
10 Nov 2020, 13:58
Kudos
Bookmarks
Fast way to solve!
1. \(\frac{1}{a}+\frac{1}{b}\)=\(\frac{1}{3}\)
2. \(2*\frac{1}{a}+\frac{1}{b}=\frac{1}{2}\) ====> \(\frac{1}{a}+\frac{1}{a}+\frac{1}{b}=\frac{1}{2}\)
Substitute 1. in 2:
\(\frac{1}{3}+\frac{1}{a}=\frac{1}{2}\)
a=6
1. \(\frac{1}{a}+\frac{1}{b}\)=\(\frac{1}{3}\)
2. \(2*\frac{1}{a}+\frac{1}{b}=\frac{1}{2}\) ====> \(\frac{1}{a}+\frac{1}{a}+\frac{1}{b}=\frac{1}{2}\)
Substitute 1. in 2:
\(\frac{1}{3}+\frac{1}{a}=\frac{1}{2}\)
a=6
