Bunuel
Machine A and machine B working at their constant respective rates produced 50 components in 20 minutes. How much time, in minutes, would it have taken machine B working alone at its constant rate to produce 50 components?
(1) Machine A produced 10 fewer components than did machine B.
(2) The rate at which machine B works is 50 percent faster than the rate at which machine A works.
The rates of machine A and B be a,b respectively.
Both working together produces 50 components in 20 minutes.
Time taken by B alone to produce 50 components?
Statement 1: (1) Machine A produced 10 fewer components than did machine B.
Given A +B =50
A = B-10
B-10 + B =50 , this gives B = 30 . Then A =20
rate of machines A and B are
a = 20/20 =1 component per minute.
b = 30/20 = 1.5 component per minute.
knowing the rate of B and the total components created (50), we can find the time. Hence
SUFFICIENT Statement 2: (2) The rate at which machine B works is 50 percent faster than the rate at which machine A works.
b = 3/2 a . Hence,
b:a = 3:2 Rates of machine B : machine A knowing the rate of B and the total components created (50), we can find the time.
Hence SUFFICIENT
Option D