Bunuel
Machine J runs at a constant rate and produces a lot consisting of 300 bottles in 4 hours. How much less time would it take to produce the lot of cans if both machines J and P were run simultaneously?
(1) Machines J and P start working simultaneously at 7 a.m.
(2) Machines J and P finish one lot by 7:23 a.m.
Let the rate of J be
a bottles/hour, and the rate of P be
b bottles/ hour.
One lot equals 300 = rate * hour
= a * 4
This,
a= 75 bottles/ hour.
We need to find : How much less time between machines J and P.
Statement 1:
(1) Machines J and P start working simultaneously at 7 a.m.
We have the start time, but we don’t have the end times or rates of P. Hence,
Insufficient Statement 2:
(2) Machines J and P finish one lot by 7:23 a.m.
300 bottles are produced by both P + J combined by 7:23 am.
Without knowing the start time, we don’t have the start times or rates of P. Hence,
Insufficient. Combining both statements 1 and 2, we get Both take 23 mins, while J working alone takes 4 hrs.
How much less time = 4 hrs - 23 mins =
3 hrs 37 mins
Option C