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# Machines X and Y produced identical bottles at different

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Director
Joined: 13 Nov 2003
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Machines X and Y produced identical bottles at different [#permalink]

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05 Jan 2004, 20:50
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Machines X and Y produced identical bottles at different constant rates. Machine X, operating alone for 4 hours, filled part of a production lot; then machine Y, operating alone for 3 hours, filled the rest of this lot. How many hours would it have taken machine X operating alone to fill the entire production lot?

(1) Machine X produced 30 bottles per minute.
(2) Machine X produced twice as many bottles in 4 hours as machine Y produced in 3 hours.

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Intern
Joined: 24 Nov 2003
Posts: 30

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Location: Champaign

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05 Jan 2004, 21:06
Machines X and Y produced identical bottles at different constant rates. Machine X, operating alone for 4 hours, filled part of a production lot; then machine Y, operating alone for 3 hours, filled the rest of this lot. How many hours would it have taken machine X operating alone to fill the entire production lot?

(1) Machine X produced 30 bottles per minute.
(2) Machine X produced twice as many bottles in 4 hours as machine Y produced in 3 hours.

--------------------------------------------------------------------------------
SOLN:

X = x bottles/hr
Y = y bottles/hr

4x + 3y = full container = Ax , A number of hrs to fill the container ---- I

1 - tells me nothing about relation between X & Y
2 - tells me
4x = 2*3y = 6y => 3y = 2x, fill this into the equation I
4x + 2x = 6x, 6 hrs

Hence 2 alone is the answer, 1 is useless information, actually it is extra info.

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Director
Joined: 14 Oct 2003
Posts: 582

Kudos [?]: 58 [0], given: 0

Location: On Vacation at My Crawford, Texas Ranch

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05 Jan 2004, 21:08
I got c)

we need to know the entire production lot and the rates of each machine.

1) Insuffeesh

2) Insuffeesh

1) tells us machine X produced 4800 bottles in its shift nothing about the entire production lot.

2) Work = Rate x Time

Tells us machine X produced twice as many bottles as machine Y. Thus, Wx = 2Wy

Thus Rx X 4= 2 (Ry X 3) = Rx/Ry = 3

Having both we would know Ry's Rate

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Director
Joined: 14 Oct 2003
Posts: 582

Kudos [?]: 58 [0], given: 0

Location: On Vacation at My Crawford, Texas Ranch

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05 Jan 2004, 21:10
I fell off the wagon on this. I agree it's B.

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Director
Joined: 13 Nov 2003
Posts: 957

Kudos [?]: 178 [0], given: 0

Location: Florida

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05 Jan 2004, 21:16
Titleist wrote:
I fell off the wagon on this. I agree it's B.

gotcha..yeh, It's B
I must be under the influence of some other bottle

thanks!

Kudos [?]: 178 [0], given: 0

Director
Joined: 14 Oct 2003
Posts: 582

Kudos [?]: 58 [0], given: 0

Location: On Vacation at My Crawford, Texas Ranch

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05 Jan 2004, 21:19
maybe 1 more problem then I'll go watch the season premier of curb your enthusiasm on VOD.

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Director
Joined: 13 Nov 2003
Posts: 957

Kudos [?]: 178 [0], given: 0

Location: Florida

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05 Jan 2004, 21:22
Titleist wrote:
maybe 1 more problem then I'll go watch the season premier of curb your enthusiasm on VOD.

here u go..easy one:

For any numbers a and b, a ┬╖ b = a + b тАУ ab. If a ┬╖ b = 0, which of the following CANNOT be a value of b?
(A) 2
(B) 1
(C) 0
(D) -1
(E) -3/2

Kudos [?]: 178 [0], given: 0

Director
Joined: 14 Oct 2003
Posts: 582

Kudos [?]: 58 [0], given: 0

Location: On Vacation at My Crawford, Texas Ranch

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05 Jan 2004, 21:41
Oh dj - I just came back from the fridge. What did you leave here for me??? A function proble m???

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Director
Joined: 14 Oct 2003
Posts: 582

Kudos [?]: 58 [0], given: 0

Location: On Vacation at My Crawford, Texas Ranch

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05 Jan 2004, 21:44
dj wrote:
Titleist wrote:
maybe 1 more problem then I'll go watch the season premier of curb your enthusiasm on VOD.

here u go..easy one:

For any numbers a and b, a ┬╖ b = a + b тАУ ab. If a ┬╖ b = 0, which of the following CANNOT be a value of b?
(A) 2
(B) 1
(C) 0
(D) -1
(E) -3/2

Let's see,

a @ b = 0 and a + b - ab

thus, a + b(1-a)=0

if I choose 1 as b, then

a+ 1(1-a)=0, thus 1=0

c? can I go watch tv???

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Director
Joined: 13 Nov 2003
Posts: 957

Kudos [?]: 178 [0], given: 0

Location: Florida

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05 Jan 2004, 21:52
titleist, you were to the point, but missed in picking up the right answer.

as you showed 1=0 when b=1, which is not possible. Hence, the answer

B

Kudos [?]: 178 [0], given: 0

Director
Joined: 14 Oct 2003
Posts: 582

Kudos [?]: 58 [0], given: 0

Location: On Vacation at My Crawford, Texas Ranch

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05 Jan 2004, 21:54
dj wrote:
titleist, you were to the point, but missed in picking up the right answer.

as you showed 1=0 when b=1, which is not possible. Hence, the answer

B

thanks I will drink my beer and watch my show now! hahaha. Good night!

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Director
Joined: 14 Oct 2003
Posts: 582

Kudos [?]: 58 [0], given: 0

Location: On Vacation at My Crawford, Texas Ranch

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05 Jan 2004, 21:55
Dj, that's the second time tonight that I got the answer right and the question choice wrong. Case and point - no more GMAT problems for me tonight! Buenos Nachos!

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SVP
Joined: 30 Oct 2003
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Location: NewJersey USA

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09 Jan 2004, 23:34
Let n be number of bottles produced by X and n by Y
m+n = total number of bottles
since m = 2n n = m/2
The machine X working alone should finish m/2 additional bottles
for m it takes 4 hours for m/2 it will take 2 hours
so 6 hours are needed.

B is sufficient

Kudos [?]: 114 [0], given: 0

09 Jan 2004, 23:34
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