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Martha takes a road trip from point A to point B. She drives [#permalink]

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14 May 2005, 06:43

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56% (02:01) correct
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Martha takes a road trip from point A to point B. She drives x percent of the distance at 60 miles per hour and the remainder at 50 miles per hour. If Martha's average speed for the entire trip is represented as a fraction in its reduced form, in terms of x, which of the following is the numerator?

Martha's Average Speed - Question 13 of Guide 2 [#permalink]

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10 Nov 2011, 16:03

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Martha takes a road trip from point A to point B. She drives x percent of the distance at 60 miles per hour and the remainder at 50 miles per hour. If Martha's average speed for the entire trip is represented as a fraction in its reduced form, in terms of x, which of the following is the numerator?

A)110 B) 300 C)1,100 D)3,000 E) 30,000

Guys - the answer for this question is not provided. I have calculated and got 30000 i.e. E. Can someone please tell me whether my answer is correct or incorrect?
_________________

Re: Martha's Average Speed - Question 13 of Guide 2 [#permalink]

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11 Nov 2011, 12:35

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BDSunDevil wrote:

i keep getting 30,000.

@ kostyan5: x% 0f D is xD/100, so t1 is xD/6000 isn't it? what am i doing wrong?

Yes, you are right. I didn't realize that percent (/100) doesn't cancel out at the end because there's on x in D. So we do need to express d1 and d2 in terms of x/100. I'm going to modify my solution above.

Re: Martha takes a road trip from point A to point B. She drives [#permalink]

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04 Jul 2014, 03:34

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Re: Martha takes a road trip from point A to point B. She drives [#permalink]

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20 Feb 2016, 19:13

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Re: Martha takes a road trip from point A to point B. She drives [#permalink]

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22 Feb 2017, 12:44

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Martha takes a road trip from point A to point B. She drives [#permalink]

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25 Aug 2017, 08:11

Assuming x=50, i.e. 50% road with speed of 60mph and remaining 50% with speed of 50mph. Now knowing formula for average speed (when distance traveled is same) = \(\frac{2ab}{a+b}\), (a,b are speeds) average speed in our case = \(\frac{2*50*60}{50+60} = \frac{2*50*60}{110} = \frac{2*300}{11}\) Question asking in terms of x,i.e. 50% = \(\frac{1}{2}\) thus \(\frac{1}{2}*\frac{2*300}{11}*100\) Numerator = 30000 Thus option E _________________

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