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Mary has p pencils and q pens in her bag while Sam has r pencils and

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Mary has p pencils and q pens in her bag while Sam has r pencils and  [#permalink]

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New post 20 Feb 2018, 02:05
2
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A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

74% (01:19) correct 26% (01:24) wrong based on 54 sessions

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Mary has p pencils and q pens in her bag while Sam has r pencils and s pens in his bag. If Mary and Sam pick up an item at random from their respective bags, who among them has a higher probability of picking up a pencil?

1) p > r
2) q > s

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Re: Mary has p pencils and q pens in her bag while Sam has r pencils and  [#permalink]

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New post 20 Feb 2018, 02:33
saswata4s wrote:
Mary has p pencils and q pens in her bag while Sam has r pencils and s pens in his bag. If Mary and Sam pick up an item at random from their respective bags, who among them has a higher probability of picking up a pencil?

1) p > r
2) q > s



Mary has p pencils and q pens

Sam has r pencils and s pens


we need more probability

statement 1 - p>r

we know nothing about q and s

statement 2 - q>s

we know nothing about p and r

combining 1 and 2

we know p > r and q >s

now it may seem that it's sufficient


but if p = a large value and so is q and r and s are 1 and 2

r/s value will be higher than p/q

thus CBD

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Re: Mary has p pencils and q pens in her bag while Sam has r pencils and  [#permalink]

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New post 23 Feb 2018, 09:43
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saswata4s wrote:
Mary has p pencils and q pens in her bag while Sam has r pencils and s pens in his bag. If Mary and Sam pick up an item at random from their respective bags, who among them has a higher probability of picking up a pencil?

1) p > r
2) q > s


Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

The question asks if p / ( p + q ) > r / ( r + s ).

Since we have 4 variables (p, q, r and s) and 0 equations, E is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2) :
p = 2, q = 3, r = 1, s = 2 : Yes
p = 2, q = 100, r = 1, s = 2 : No

Since we don't have a unique solution, both conditions 1) & 2) together are not sufficient.

In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2), when taken together. Obviously, there may be occasions on which the answer is A, B, C or D.
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Re: Mary has p pencils and q pens in her bag while Sam has r pencils and  [#permalink]

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New post 25 Feb 2018, 00:15
saswata4s wrote:
Mary has p pencils and q pens in her bag while Sam has r pencils and s pens in his bag. If Mary and Sam pick up an item at random from their respective bags, who among them has a higher probability of picking up a pencil?

1) p > r
2) q > s


I & II are clearly insufficient.

Combining I & II:

We have to find \(\frac{p}{p+q}\) and \(\frac{r}{r+s}\).
Also, \(p+q > r+s.\)
But we don't know the value of \(p & r.\)

Hence, Insufficient. E
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Re: Mary has p pencils and q pens in her bag while Sam has r pencils and  [#permalink]

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New post 26 Feb 2018, 22:00
saswata4s wrote:
Mary has p pencils and q pens in her bag while Sam has r pencils and s pens in his bag. If Mary and Sam pick up an item at random from their respective bags, who among them has a higher probability of picking up a pencil?

1) p > r
2) q > s

IMO is E probability of mary picking up pencil is p/p+q and probability of sam picking up pencil is r/r+s
now we don't know whether p/p=q is greater or r/r+s is greater now lets come to statement
1st statement p>r but we don't know about q and s. insufficient.
2nd statement q>s but we don't know about p and r so insufficient.
combining both we can't say anything as we don't know how much greater or if sign is flipped then c is possible .
so E is the answer.
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Re: Mary has p pencils and q pens in her bag while Sam has r pencils and &nbs [#permalink] 26 Feb 2018, 22:00
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Mary has p pencils and q pens in her bag while Sam has r pencils and

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