Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 1408:30 AM PDT
-09:30 AM PDT
Most GMAT test-takers are intimidated by the hardest GMAT Verbal questions. In this session, Target Test Prep GMAT instructor Erika Tyler-John, a 100th percentile GMAT scorer, will show you how top scorers break down challenging Verbal questions..
May 1212:00 PM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products.- May 13
08:30 AM PDT
-09:30 AM PDT
In Episode 4 of our GMAT Ninja CR series, we tackle the most intimidating CR question type: Boldface & "Legalese" questions. If you've ever stared at an answer choice that reads, "The first is a consideration introduced to counter a position that... - Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
06 Oct 2016, 05:57
Kudos
Bookmarks
On six seating chairs including one red chair around a big round table , A, B, C, D, E, F each sit on a chair. A must sit on the red chair and B must be beside A. How many seating arrangement are?
A. 36 B. 40 C. 44 D. 48 E. 64
==> If you set A, and B sits on the left side of A, the rest can be seated with the number of cases of 4*3*2*1=24. If B sits on the right side of A, there can be 24 number of cases that they can be seated. Hence, 24+24=48. The answer is D.
Answer: D
A. 36 B. 40 C. 44 D. 48 E. 64
==> If you set A, and B sits on the left side of A, the rest can be seated with the number of cases of 4*3*2*1=24. If B sits on the right side of A, there can be 24 number of cases that they can be seated. Hence, 24+24=48. The answer is D.
Answer: D
10 Oct 2016, 05:48
Kudos
Bookmarks
There is a sequence An=1-1/(n+1). What is the product of all the first 100 terms?
A. 1/99 B. 1/100 C. 1/101 D. 99/100 E. 100/101
==> An=1-1/(n+1)=n/(n+1) then,
A1A2…….A99A100=(1/2)(2/3)….(99/100)(100/101)=1/101
Hence, C is the answer.
Answer: C
A. 1/99 B. 1/100 C. 1/101 D. 99/100 E. 100/101
==> An=1-1/(n+1)=n/(n+1) then,
A1A2…….A99A100=(1/2)(2/3)….(99/100)(100/101)=1/101
Hence, C is the answer.
Answer: C
12 Oct 2016, 03:35
Kudos
Bookmarks
What is the units digit of 6^m(2^7+1), for a positive integer m?
A. 1
B. 3
C. 4
D. 7
E. 0
==> 6m=~6, then 2^7+1=(~8)+1=~9, so 6^m(2^7+1)=(~6)(~9)=~4
Hence C is the answer.
Answer: C
A. 1
B. 3
C. 4
D. 7
E. 0
==> 6m=~6, then 2^7+1=(~8)+1=~9, so 6^m(2^7+1)=(~6)(~9)=~4
Hence C is the answer.
Answer: C
