If sphere A’s volume is 64 times of sphere B’s volume, sphere A’s surface area is how many times of sphere B’s surface area?
A. 4 B. 8 C. 12 D. 16 E. 32
==> Since sphere A’s volume is 64 times of sphere B’s volume, sphere A’s length is Sphere A’s \(3√64\)times of sphere B’s length, in other words,\(3√4^3=4\). However, since the ratio of the surface area is equal to the square of ratio of the length, you get 4^2=16, hence 16 times.
Therefore, the answer is D.
Answer: D