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05 Apr 2017, 01:22
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If (4/9)÷n=3/5, n=?
A. 20/27
B. 27/20
C. 10/9
D. 9/10
E. 9/4
==>(4/9)÷n=3/5 -> (4/9)(1/n)=3/5. And 4/9n=3/5 -> n=(4/9)(5/3)=20/27.
Hence, the answer is A.
Answer: A
A. 20/27
B. 27/20
C. 10/9
D. 9/10
E. 9/4
==>(4/9)÷n=3/5 -> (4/9)(1/n)=3/5. And 4/9n=3/5 -> n=(4/9)(5/3)=20/27.
Hence, the answer is A.
Answer: A
06 Apr 2017, 01:02
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\(\frac{2^{x-1}}{2^{1-x}}\) is equal to which of the following?
A. \(4^{x-1}\)
B. \(4^{1-x}\)
C. \(4^{2x}\)
D. \(4^{-2x}\)
E. \(4^x\)
==> You get \(\frac{2^{x-1}}{2^{1-x}} =2^{x-1-(1-x)}=2^{2(x-1)}=4^{x-1}\).
The answer is A.
Answer: A
A. \(4^{x-1}\)
B. \(4^{1-x}\)
C. \(4^{2x}\)
D. \(4^{-2x}\)
E. \(4^x\)
==> You get \(\frac{2^{x-1}}{2^{1-x}} =2^{x-1-(1-x)}=2^{2(x-1)}=4^{x-1}\).
The answer is A.
Answer: A
07 Apr 2017, 02:02
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It’s well known that a company's profit=10,000x-50x^2, where x is the number of workers. If the profit of the company is the greatest, what is the value of x?
A. 5
B. 10
C. 50
D. 80
E. 100
==> From \(y=f(x)=ax^2+bx+c\), if \(x=\frac{-b}{2a}\), f(x) becomes either maximum or minimum. Thus, profit=\(-50x^2+10,000x\), and in order for the profit to become the greatest, you get \(x=\frac{-10,000}{2(-50)}=100\).
The answer is E.
Answer: E
A. 5
B. 10
C. 50
D. 80
E. 100
==> From \(y=f(x)=ax^2+bx+c\), if \(x=\frac{-b}{2a}\), f(x) becomes either maximum or minimum. Thus, profit=\(-50x^2+10,000x\), and in order for the profit to become the greatest, you get \(x=\frac{-10,000}{2(-50)}=100\).
The answer is E.
Answer: E
