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# Math Revolution Approach (DS)

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Intern
Joined: 26 Nov 2016
Posts: 6
Re: Math Revolution Approach (DS) [#permalink]

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08 Dec 2016, 00:17
MathRevolution wrote:
At least 10 cars have tinting window and fog light. 40% cars which have tinting windows also have fog light, is the number of the cars with tinting windows larger than that of the cars with the fog light?
1) 80% cars which have fog light also have tinting windows
2) 52 cars have tinting windows or fog light or both

ANS: If we were to solve this question with our trick, we should observe if one of conditions include ratio. If one of conditions contains ratio, then the condition with ratio has 90% of chance to become the answer. Since the condition 1) has ratio, the correct answer is A.

Can you please explain the solution in detail

Sent from my C6902 using GMAT Club Forum mobile app
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5837
GMAT 1: 760 Q51 V42
GPA: 3.82
Re: Math Revolution Approach (DS) [#permalink]

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08 Dec 2016, 01:38
a, b, c, d, and e are integers. Is the median of the integers greater than the average (arithmetic mean) of the integers?

1) a<b<c<d<e
2) b-a=e-d

==> In the original condition, there are 5 variables, so E is most likely to be the answer.
By solving con 1) & con 2), you get (a,b,c,d,e)=(1,2,3,4,5), hence it is no, and you get (a,b,c,d,e)=(1,2,101,102,103),
hence it is yes, so it is not sufficient. Therefore, the answer is E.

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"Only $99 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5837 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: Math Revolution Approach (DS) [#permalink] ### Show Tags 09 Dec 2016, 01:44 Is x<y<z? 1) x-2<y-1<z 2) x+2<y+1<z ==> In the original condition, there are 3 variables (x, y, z), so E is most likely to be the answer. By solving con 1) & con 2), you get 2x<2y<2z. From x<y<z, it is always yes, hence it is sufficient. However, if you look at con 2), from x+1<x+2<y+1<z<z+1, you get x+1<y+1<z+1, and x<y<z, so it is always yes, hence it is sufficient. Therefore, the answer is B. Answer: B _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$99 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5837
GMAT 1: 760 Q51 V42
GPA: 3.82
Re: Math Revolution Approach (DS) [#permalink]

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10 Dec 2016, 19:32
Hemanth2017 wrote:
MathRevolution wrote:
At least 10 cars have tinting window and fog light. 40% cars which have tinting windows also have fog light, is the number of the cars with tinting windows larger than that of the cars with the fog light?
1) 80% cars which have fog light also have tinting windows
2) 52 cars have tinting windows or fog light or both

ANS: If we were to solve this question with our trick, we should observe if one of conditions include ratio. If one of conditions contains ratio, then the condition with ratio has 90% of chance to become the answer. Since the condition 1) has ratio, the correct answer is A.

Can you please explain the solution in detail

Sent from my C6902 using GMAT Club Forum mobile app

Hi Hemanth2017,

In general, one con is % and if one con is number, % is likely to be an answer.
When it comes to 1), amongst cars with tinting windows, 40% of them have fog light.
For the same cars with fog light, 80% have tinting windows.
For instance, cars with only tinting window - six cars, both tinting window and fog light - four cars, only fog light - one car, which is 10>5 and yes.

Happy Studying!
_________________

MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
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"Only $99 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5837 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: Math Revolution Approach (DS) [#permalink] ### Show Tags 12 Dec 2016, 01:12 If the ratio of a to b to c to d is 1 to 2 to 3 to 4, what is the range of a, b, c and d? 1) The average (arithmetic mean) of b and d is 9 2) The sum of a and d is 15 ==> If you modify the original condition and the question and look at the question again, from a=k, b=2k, c=3k, d=4k, there are 5 variables (a, b, c, d, k), and 4 equations. Therefore, D is most likely to be the answer. Con 1) = con 2), so k=3, and from range=d-a=4k-k=3k=3(3) = 9, it is sufficient. Therefore, D is the answer. Answer: D _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$99 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5837
GMAT 1: 760 Q51 V42
GPA: 3.82
Re: Math Revolution Approach (DS) [#permalink]

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12 Dec 2016, 01:14
What is the standard deviation (d) of m, n, p?

1) m, n, and p are different
2) $$d^2-2d=0$$

==> From the original condition, there are 3 variables, and therefore E is most likely to be the answer. By solving con 1) & con 2), from d(d-2)=0, you get d=0, 2. From con 1), m, n, and p are different and d≠0, it is always d=2 only, so it is unique and sufficient.

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"Only $99 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5837 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: Math Revolution Approach (DS) [#permalink] ### Show Tags 14 Dec 2016, 01:27 What is the median of 5 numbers? 1) Each of the 3 numbers is 11 2) The 2 greatest numbers of them are 21 and 25 ==> If you modify the original condition and the question, the median of 5 numbers become the third number. In case of con 1), from 11,11,11,( ),( ) or ( ),11,11,11,( ) or ( ), ( ),11,11,11, it is always median=11, so it is unique and sufficient. Therefore, the answer is A. Answer: A _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$99 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5837
GMAT 1: 760 Q51 V42
GPA: 3.82
Re: Math Revolution Approach (DS) [#permalink]

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15 Dec 2016, 01:12
If x≠0, |x|/x=?
1) x<0
2) x=-1

==> If you modify the original condition and the question, you get |x|=-x (x<0). Thus, if x<0, you get |x|/x=-x/x=-1, so con 1) = con 2), and therefore the answer is D.
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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
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"Only $99 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5837 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: Math Revolution Approach (DS) [#permalink] ### Show Tags 16 Dec 2016, 00:37 If the average (arithmetic mean) of 3 integers a, b, and c is 5, what is the value of a? 1) b=7 2) b=1-c ==> If you modify the original condition and the question and look at the question again, from a+b+c=15, you get a=15-(b+c), so you only need to know b+c. From con 2), you get b+c=1, so from a=15-(b+c)=15-1=14, it is unique and sufficient. Therefore, the answer is B. This question is related to mistake type 4(A). Answer: B _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$99 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5837
GMAT 1: 760 Q51 V42
GPA: 3.82
Re: Math Revolution Approach (DS) [#permalink]

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18 Dec 2016, 18:18
If x and y are prime numbers, what is the smallest prime factor of $$xy^3$$ ?

1) x=even
2) x+y=odd

==> In the original condition, there are only 2 variables (x, y), hence C is most likely to be the answer. For con 1), if x=even, an even number that is also a prime number is only “2”, so the smallest prime factor of $$xy^3$$ becomes 2, and hence it is sufficient.
For con 2), in order to get x+y=odd, since it is even+odd=odd, x or y always becomes “2”, so the smallest prime factor of $$xy^3$$ becomes “2”, and hence it is also sufficient.
This question is also related to mistake type 4(B), where con 1) is easy and con 2) is difficult. This type of question is a 5051-level question.

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"Only $99 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5837 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: Math Revolution Approach (DS) [#permalink] ### Show Tags 18 Dec 2016, 18:23 If $$a^3b^4c^5<0$$, is $$ab^2<0$$? 1) a<0 2) c>0 ==> If you modify the original condition and the question and look at the question again, from If $$a^3b^4c^5<0$$, there are only odd variables, so you get If ac<0. Then, the que is $$ab^2<0$$? becomes a<0?, and hence con 1) is yes and sufficient. Also, from ac<0, you get c>0?, and hence con 2) is yes and sufficient. Therefore, the answer is D. Answer: D _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$99 for 3 month Online Course"
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Joined: 16 Aug 2015
Posts: 5837
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GPA: 3.82
Re: Math Revolution Approach (DS) [#permalink]

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21 Dec 2016, 01:43
If ab=c, b=?
1) c≠0
2) |a-c|≤0

==> In the original condition, there are 3 variables (a, b, c) and 1 equation (ab=c). In order to match the number of variables to the number of equations, there must be 2 equations, and therefore C is most likely to be the answer.
By solving con 1) and con 2), from con 2), you get a=c, and if you substitute this into ab=x, you get ab=a. In order to divide a from both sides, it needs to be a≠0. From con 1), it is c=a≠0, and if you divide both sides by a, you get b=1, hence it is unique and sufficient.

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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
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"Only $99 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5837 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: Math Revolution Approach (DS) [#permalink] ### Show Tags 23 Dec 2016, 02:27 If x, y and z are different integers, what is the value of y? 1) The average (arithmetic mean) of x, y and z is 2 2) x<y<z ==> In the original condition, there are 3 variables (x, y, z), and in order to match the number of variables to the number of equations, there must be 3 equations, and therefore E is most likely to be the answer. By solving con 1) & con 2), you get (x+y+z)/3=2. Since it is x<y<z, you always get median=average=y=2. Hence it is unique and sufficient. The answer is C. Answer: C _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$99 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5837
GMAT 1: 760 Q51 V42
GPA: 3.82
Re: Math Revolution Approach (DS) [#permalink]

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25 Dec 2016, 18:34
If r and s are positive integers, is r+s an odd number?
1) r and s are consecutive
2) r=s+1

==> In the original condition, there are 2 variables (r, s), and therefore C is most likely to be the answer. By solving con 1) & con 2), you get con 1) = con 2), so it becomes r+s=s+1+s=2s+1=odd, and hence it is yes and sufficient.

This is a 5051-level question related to mistake type 4(B).
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"Only $99 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5837 GMAT 1: 760 Q51 V42 GPA: 3.82 If x and y are positive integers, xy-2=? [#permalink] ### Show Tags 25 Dec 2016, 18:37 If x and y are positive integers, $$x^y^-^2$$=? 1) $$x^2=1$$ 2) $$y^2=4$$ ==> In the original condition, there are 2 variables (x), and in order to match the number of variables to the number of equations, there must be 2 equations, and therefore C is most likely to be the answer. By solving con 1) & con 2), you get x=-1, 1 and y=-2, 2. Since x and y are positive integers, only x=1 and y=2 are possible, and con 1) becomes $$1^y^-^2=x^2^-^2=x^0=1$$. Therefore, the answer is D. _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$99 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5837
GMAT 1: 760 Q51 V42
GPA: 3.82
Re: Math Revolution Approach (DS) [#permalink]

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31 Dec 2016, 01:43
If a and b are integers, is ab an odd?

1) a=0
2) b=1-a

==> In the original condition, there are 2 variables (a, b), and therefore C is most likely to be the answer. By solving con 1) and con 2), from a=0 and b=1, you get ab0*1=0=even, hence no, it is sufficient. Therefore, C is the answer. However, this is an integer question, one of the key questions. Thus, if you apply CMT 4 (A, B), if 1) a=0, you get ab=0 and it is always even, hence no, it is sufficient. Also, for con 2), from a+b=1=odd, and (a, b)=(odd, even), (even, odd), you get ab=even, hence yes, it is sufficient. Therefore, the answer is D. This question is related to CMT 4(B). In other words, con 1) is easy and con 2) is difficult, so you apply CMT 4(B) (If you get A and B easily, consider B).
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"Only $99 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5837 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: Math Revolution Approach (DS) [#permalink] ### Show Tags 31 Dec 2016, 01:48 Is n an even number? 1) n(n+1)/2 is an even number 2) n(n+2) is an even number ==> In the original condition, there is 1 variable (n), and therefore D is most likely to be the answer. However, for con 1), you get n=3 no, n=8 yes, and hence it is not sufficient, and for con 2), in order to get n(n+2)=even, you need to get n=even, and hence yes, it is sufficient. Therefore, the answer is B. Answer: B _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$99 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5837
GMAT 1: 760 Q51 V42
GPA: 3.82
Re: Math Revolution Approach (DS) [#permalink]

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31 Dec 2016, 01:49
Is 1/a>1/b?
1) a<b
2) a<b<0

==> If you modify the original condition and the question and check the question again, you get a<b<0--> 1/a>1/b. In other words, it does not become a<b --> 1/a>1/b.

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"Only $99 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5837 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: Math Revolution Approach (DS) [#permalink] ### Show Tags 01 Jan 2017, 18:38 If ab=0, is |a-b|>0? 1) a=0 2) b<0 ==> If you modify the original condition and the question, you get is a≠b? Also, there are 2 variables (a, b) and 1 equation (ab=0), in order to match the number of variables to the number of equations, there must be 1 equation as well, and therefore D is most likely to be the answer. For con 1), you get a=b=0 no a=0 and b=3, hence yes, it is not sufficient. For con 2), you get b<0 and a=0, hence yes, it is sufficient. Therefore, the answer is B. Answer: B _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$99 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5837
GMAT 1: 760 Q51 V42
GPA: 3.82
Re: Math Revolution Approach (DS) [#permalink]

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01 Jan 2017, 18:40
If m and n are positive integers, is $$10^n$$+m divisible by 3?
1) n=1
2) m=2

==> If you modify the original condition and the question, “Is $$10^n$$+m=3t? (t=any positive integer)” is equal to “Is the sum of all the digits of $$10^n$$+m divisible by 3?” Then, as from con 2), if you know m=2, from $$10^n$$+2 => 12, 102, 1002…., the sum of the digits always become 3, which is divisible by 3, and hence yes, it is sufficient.

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Re: Math Revolution Approach (DS)   [#permalink] 01 Jan 2017, 18:40

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