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Math Revolution Approach (DS)

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New post 04 Jul 2016, 23:39
Is x^2>y^2?
1) x<y
2) -y>x

Ans: From the original condition, we can see that there are 2 variables. Hence, the correct answer is C.
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New post 05 Jul 2016, 21:12
1
If a and b are non-negative integers, ab=?
1) 9^a=3^b
2) 5^a=2^b

ANS: From the original condition, there are 2 variables. Hence, there is a high chance that C is the correct answer. However, since this is an integer question, one of key questions, we should apply the common mistake type 4(A). From con 1), we get 2a=b. The answer is not unique and the condition is not sufficient. In case of con 2), we get a=b=0. The answer is unique and the condition is sufficient. Hence, the correct answer is B.
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New post 06 Jul 2016, 16:50
1
If x, y are positive integers, what is the remainder when 2^(8x+y) is divided by 5?
1) x=1
2) y=2

ANS: From the original condition, there are 2 variables (x and y). In order to match the number of variables and the number of equations, we need 2 equations. Hence, there is a high chance that C is the correct answer. However, even though C is indeed the correct answer, since it is an integer question, one of the key questions, we have to apply the common mistake type 4(A). From the condition 2), the remainder of 2^(8x+y) is always 4. Hence, it is sufficient and the correct answer is B.
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New post 08 Jul 2016, 21:41
Is x+y>0?
1) x>|y|
2) y<0
ANS: In case of con 1), from x>|y|≥-y, we get x>-y, x+y>0. The answer is yes and the condition is sufficient. Hence, the correct answer is A
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New post 11 Jul 2016, 00:43
If x, y are positive integers, what is the unit digit of 2^(4x+2)+y?
1) x=1
2) y=2

ANS: In the original condition, there are 2 variables (x and y). Hence, there is a high chance that C is the correct answer. Using 1) & 2), C is the correct answer. However, since this is an integer question, we can apply the common mistake type 4(A). From con 2), the unit digit of 2^4x+2 is always 5. Hence, we only have to know y, and the condition is sufficient. The correct answer, thus, is B.
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New post 11 Jul 2016, 00:45
If 0<x<y, is x<4?
1) (1/x)+(1/y)=1/2
2) 1/x>1/4

ANS: Since there are 2 variables in the original condition, there is a high chance that C is the correct answer. Condition 2) becomes the answer too easily because from 1/x>1/4, we get 0<x<4. The condition is sufficient. However, the condition is rather too hard. If we apply the common mistake type 4(B), the answer becomes D.
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New post 11 Jul 2016, 18:28
Is a=b?
1) a^2=b^2
2) a=1

ANS: There are 2 variables in the original condition. In order to match the number of variables and the number of equations, we need 2 equations. There is a high chance that C is the correct answer. Using 1) & 2), from a=1 and b=-1, 1, the answer is both yes or no. Hence, the conditions are not sufficient and the correct answer is E.
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New post 12 Jul 2016, 18:57
Is a=b?
1) a^2=b^2
2) a=1

ANS: There are 2 variables in the original condition. Hence, we need 2 equations, and there is a high chance that C is the correct answer. Using 1) & 2), from a=1 and b=-1, 1, the answer is both yes and no. The conditions are not sufficient and the correct answer is E.
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New post 14 Jul 2016, 01:08
1
What is the perimeter of a certain right triangle?

1) The hypotenuse’s length is 5
2) The triangle’s area is 4.5

ANS: From the original condition, we can see that the number of variables is 2. Hence, the number of equations we need is 2 as well. The correct answer is C
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New post 14 Jul 2016, 21:25
2^(x+y)/2^(x-y)=?
1) x=1
2) y=2

ANS: If we modify the original condition and the question, we get 2^(x+y)/2(x-y)=? --> 2^((x+y)-(x-y))=2^2y. We only have to know y and the correct answer is B.
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New post 18 Jul 2016, 04:17
When a positive integer n is divided by 29, what is the remainder?
1) n-5 is divisible by 29
2) n-29 is divisible by 5

ANS: If we use direct substitution, in case of con 1), the remainder is always 5. The answer is unique and the condition is sufficient. Thus, the correct answer is A.
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New post 18 Jul 2016, 09:24
Is |a^2-b^2|<10?
1) |a-b|<5
2) |a+b|<2

ANS: Since there are 2 variables in the original condition, the correct answer is C.
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New post 24 Jul 2016, 02:42
Is a+b+c=even?
1) abc=even
2) ac=odd

ANS: Since there are 3 variables in the original condition, the correct answer is E.
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New post 25 Jul 2016, 05:50
If b is an integer greater than 1, ab=?
1) b^a=1
2) b=2

ANS: Since there are 2 variables in the original condition, there is a high chance that C is the correct answer. However, we have to apply the common mistake type 4(A) since it is an integer question, one of key questions. In case of con 1), since we have a=0, we get ab=0. The answer is unique and the condition is sufficient. Hence, the correct answer is A.
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New post 25 Jul 2016, 05:51
If a, b are positive integers (b≠1), is a/b<1/10 ?
1) a/(b-1)<1/15
2) (a-1)/b<1/15

ANS: Since there are 2 variables in the original condition, there is a high chance that C is the correct answer. Applying the common mistake type 4(A), the correct answer is A.
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New post 25 Jul 2016, 19:37
(x-y)^2-(x+y)^2=?
1) xy=5
2) x+y=6

ANS: If we modify the original condition and the question, from (x-y)^2-(x+y)^2=? --> -4xy=? Hence, we only have to know the value of xy and the correct answer is A.
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New post 26 Jul 2016, 18:28
If xy<0, is (x^2)y<0?
1) x>0
2) (x^3)y<0

ANS: Answer is A
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New post 31 Jul 2016, 09:03
u=?
1) |u|+|v|=0
2) u^2+v^2=0

*ANS: There are 2 variables in the original condition and there is a high chance that C is the correct answer. Using con 1) and con 2), we get u=v=0. Hence the correct answer is D.
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New post 04 Aug 2016, 04:45
How many 5 existed in the 11 numbers?
1) The average (arithmetic mean) of the 11 numbers is 5
2) The median of the 11 numbers is 5

*ANS: If we modify the original condition and the question, since we have 11 numbers, the median exists in these numbers. Hence, if we look at the condition 2), since the median is 5, 5 is always a part of 11 numbers. The answer is yes and the answer is B.
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Re: Math Revolution Approach (DS)  [#permalink]

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New post 04 Aug 2016, 19:21
Is xy<10?
1) x<5
2) y<2

ANS: There are 2 variables (x and y) and there is a high chance that C is the correct answer. Using con 1) and 2), the answer is yes when xy=1 and the answer is no when x=y=-5. Hence, the condition is not sufficient. So, the correct answer is E.
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Re: Math Revolution Approach (DS) &nbs [#permalink] 04 Aug 2016, 19:21

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