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15 Sep 2025, 00:38
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
65% (02:48) correct
35%
(03:17)
wrong
based on 86
sessions
History
Date
Time
Result
Not Attempted Yet
Mayank, Mirza, Little and Jaspal bought a motorbike for $60.00. Mayank paid one half of the sum of the amounts paid by the other boys. Mirza paid one-third of the sum of the amounts paid by the other boys, and Little paid one-fourth of the sum of the amounts paid by the other boys. How much did Jaspal have to pay?
A. 17
B. 15
C. 13
D. 12
E. 11
A. 17
B. 15
C. 13
D. 12
E. 11
Updated on: 15 Sep 2025, 10:25
Originally posted by findingmyself on 15 Sep 2025, 09:47.
Last edited by findingmyself on 15 Sep 2025, 10:25, edited 1 time in total.
Last edited by findingmyself on 15 Sep 2025, 10:25, edited 1 time in total.
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I am putting down the method I used here: Appreciate if anyone can share a short method.
Mayank=M
Mirza=N
Little=O
Jaspal=P
2M=N+O+P---(1)
3N=M+O+P---(2)
4O=M+N+P---(3)
M+N+O+P=60 or M+N+P=60-O
O=(M+N+P)/4---From equation 3
O=(60-O)/4
5O=60
O=12 (Sigh of relief:angel:)
N=(M+O+P)/3
N=(60-N)/3
N=15
M=(N+O+P)/2
M=(60-M)/2
3M=60
M=20
12+15+20+P=60
P=13
Mayank=M
Mirza=N
Little=O
Jaspal=P
2M=N+O+P---(1)
3N=M+O+P---(2)
4O=M+N+P---(3)
M+N+O+P=60 or M+N+P=60-O
O=(M+N+P)/4---From equation 3
O=(60-O)/4
5O=60
O=12 (Sigh of relief:angel:)
N=(M+O+P)/3
N=(60-N)/3
N=15
M=(N+O+P)/2
M=(60-M)/2
3M=60
M=20
12+15+20+P=60
P=13
15 Sep 2025, 10:17
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Bunuel
Let Mayank, Mirza, Little and Jaspal be denoted as M, Mi, L, and J.
We know that, M+ Mi+ L+ J = $60 ————- equation (1).
M = 1/2*(Mi + L + J)
Mi+ L+ J = 2M
M + 2M = 60
M = 20
Mi = (1/3)* (M + L+ J)
from eqn (1), Mi = (1/3)*(60 - Mi)
solving it, we get 4Mi = 60
Mi = 15
L = (1/4) *(M + Mi + J)
from eqn (1), L = (1/4) * (60 -L)
5L = 60
L =12
substitute these values in equation 1, we get
J = 60 - (15+12+20)
J = 13
Option C
ANOTHER APPROACH: findingmyself
After calculating the value of M = 20.
Mi = (1/3)* (M + L+ J)
Mi : (M+ L+J) = 1:3
1x + 3x = 4x = 60 , so x = 15.
Mi = 15
M+ L+ J = 3*15 = 45
L + J = 45 - M = 45- 20 = 25
L+ J = 25
L = (1/4) *(M + Mi + J)
L : (M + Mi + J) = 1: 4
5x = 60, then x = 12
We know L = x = 12
From L+ J = 25 , 12 + J = 25
So, J =13 . Option C
