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# Medals

Author Message
Manager
Joined: 29 May 2008
Posts: 110

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17 Jun 2009, 06:23
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

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Five contestants representing five different countries advance ti the final of a fencing championship. All thins being equal, how many possibilities are there with respect to how a first place and a second medal can be awarded?

A) 25
B) 20
C) 45
D) 100
E) 120

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Current Student
Joined: 03 Aug 2006
Posts: 112

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17 Jun 2009, 20:23

Direct Solution:
$$5 \times 4 = 20$$

Simplified solution:
First find the number of ways the first place can be won. As there are 5 finalists, there are exactly 5 possibilities for the first place.

Next, the number of ways second place can be won for each first place winner is exactly 4 as a finalist cannot be in both first and second place.

$$\Rightarrow$$ the first and second places can be chosen in $$5 \times 4$$or $$20$$ different ways.
Manager
Joined: 25 May 2009
Posts: 140
Concentration: Finance
GMAT Date: 12-16-2011

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18 Jun 2009, 07:36
Use permutation because order matters.

5P2 = 5!/3! = 5*4 = 20
Manager
Joined: 29 May 2008
Posts: 110

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19 Jun 2009, 07:02
It was an easy problem, you know that night when I was doing the problems I made so many that it was hard for me to distinguish how simple this problem was, thanks a lot

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: Medals   [#permalink] 19 Jun 2009, 07:02
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