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Medals

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Manager
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Joined: 29 May 2008
Posts: 110
Medals [#permalink]

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New post 17 Jun 2009, 06:23
00:00
A
B
C
D
E

Difficulty:

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Question Stats:

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Five contestants representing five different countries advance ti the final of a fencing championship. All thins being equal, how many possibilities are there with respect to how a first place and a second medal can be awarded?

A) 25
B) 20
C) 45
D) 100
E) 120

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Joined: 03 Aug 2006
Posts: 112
Location: Next to Google
Schools: Haas School of Business
Re: Medals [#permalink]

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New post 17 Jun 2009, 20:23
The answer is B

Direct Solution:
\(5 \times 4 = 20\)

Simplified solution:
First find the number of ways the first place can be won. As there are 5 finalists, there are exactly 5 possibilities for the first place.

Next, the number of ways second place can be won for each first place winner is exactly 4 as a finalist cannot be in both first and second place.

\(\Rightarrow\) the first and second places can be chosen in \(5 \times 4\)or \(20\) different ways.
Manager
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Joined: 25 May 2009
Posts: 140
Concentration: Finance
GMAT Date: 12-16-2011
Re: Medals [#permalink]

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New post 18 Jun 2009, 07:36
Use permutation because order matters.

5P2 = 5!/3! = 5*4 = 20
Manager
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Joined: 29 May 2008
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Re: Medals [#permalink]

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New post 19 Jun 2009, 07:02
It was an easy problem, you know that night when I was doing the problems I made so many that it was hard for me to distinguish how simple this problem was, thanks a lot

--== Message from GMAT Club Team ==--

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If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Re: Medals   [#permalink] 19 Jun 2009, 07:02
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