It is currently 22 Sep 2017, 08:27

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Method for factoring equations with large powers

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
1 KUDOS received
Intern
Intern
avatar
Joined: 20 May 2009
Posts: 39

Kudos [?]: 3 [1], given: 5

Method for factoring equations with large powers [#permalink]

Show Tags

New post 25 Jul 2009, 06:05
1
This post received
KUDOS
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Does anyone have a method for factoring equations with large powers

e.g. X^16 – Y^8 + 345Y^2

Thanks,

Aztec

Kudos [?]: 3 [1], given: 5

Manager
Manager
User avatar
Joined: 18 Jul 2009
Posts: 168

Kudos [?]: 114 [0], given: 37

Location: India
Schools: South Asian B-schools
Re: Method for factoring equations with large powers [#permalink]

Show Tags

New post 25 Jul 2009, 12:01
Aztec wrote:
Does anyone have a method for factoring equations with large powers

e.g. X^16 – Y^8 + 345Y^2

Thanks,

Aztec


PLZ post ur Question then it will be appropriate to see in that context
_________________

Bhushan S.
If you like my post....Consider it for Kudos :-D

Kudos [?]: 114 [0], given: 37

1 KUDOS received
Manager
Manager
User avatar
Joined: 03 Jul 2009
Posts: 106

Kudos [?]: 93 [1], given: 13

Location: Brazil
Re: Method for factoring equations with large powers [#permalink]

Show Tags

New post 25 Jul 2009, 12:49
1
This post received
KUDOS
Aztec, I would give you three suggestions:

First: Memorize those products with notable results:
\((x + a)^2 = x^2 + 2ax + a^2\)
\((x - a)^2 = x^2 - 2ax + a^2\)
\((x - a)(x + a) = x^2 - a^2\)

You need not only to memorize them, but also to recognize the inverted process. For example, you must be so familiar with those equations, that when you see something like
\(x^2 + 14x + 49\), you know that in fact this can be \((x+7)^2\).

Second: Zeros of the equations:
Remember that the zeros of the equation, are the opposite terms inside the parentheses of those equations.
For instance, if you see the equation \(m^2 - 3m -28\), you can discover the zeros, which are \(-4\) and \(7\), and reconstruct the equation with the opposite of the solutions: \(4\) and \(-7\)
Thus \((x + 4)(x - 7)\)

Third: Recognize equal terms.
If you see the equation \(3z^5 + 36z^4 - 84z^3\), you can notice that \(z^3\) is a common term in all the terms. Additionally, all the coefficients are divisible by \(3\). Thus the term \(3z^3\) is in all the terms of the equation. If you take off this term, the new equation is:
\(3z^3 (z^2 + 12z - 28)\)
You can go farther, and notice that the equation inside the parenthesis has the zeros \(2\) and \(-14\). Using the second advice listed you will have
\(3z^3 (z - 2) (z +14)\), much more simple than \(3z^5 + 36z^4 - 84z^3\)
Now, coming back to your equation, we could rewrite as \(X^16 - Y^2(Y^6-345)\). But there are other possibilities. If this is above some fraction, or even in some other context, it is a little bit easier to realize what factoring we should do. ;)

Good studies!!!

PS.: If you liked the explanation, consider a kudo. I want to access those GMATClub tests!!! ;)

Kudos [?]: 93 [1], given: 13

Intern
Intern
avatar
Joined: 20 May 2009
Posts: 39

Kudos [?]: 3 [0], given: 5

Re: Method for factoring equations with large powers [#permalink]

Show Tags

New post 27 Jul 2009, 14:05
Thanks a lot coelholds :-)
These tips are useful.

Kudos [?]: 3 [0], given: 5

Manager
Manager
User avatar
Joined: 03 Jul 2009
Posts: 106

Kudos [?]: 93 [0], given: 13

Location: Brazil
Re: Method for factoring equations with large powers [#permalink]

Show Tags

New post 27 Jul 2009, 16:28
You are welcome :)

Kudos [?]: 93 [0], given: 13

Re: Method for factoring equations with large powers   [#permalink] 27 Jul 2009, 16:28
Display posts from previous: Sort by

Method for factoring equations with large powers

  post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.