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# MGMAT Problem 2.

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Director
Joined: 01 May 2007
Posts: 793

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21 Jun 2008, 11:56
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Can anyone solve this not picking #s, and by using logic?

What is the remainder when 25 is divided by positive integer j?

(1) j is even.

(2) j < 9
Senior Manager
Joined: 06 Mar 2006
Posts: 489

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21 Jun 2008, 19:35
jimmyjamesdonkey wrote:
Can anyone solve this not picking #s, and by using logic?

What is the remainder when 25 is divided by positive integer j?

(1) j is even.

(2) j < 9

Statement 1, if j is an even number and also happen to be a multiple of 5, the remiander will be different from if j is an even number and not a multiple of 5, so this is insufficient

Statement 2, j<9 contains no even number which also happen to be a multiple of 5, so the remainder will always be 1; therefore, sufficient

Intern
Joined: 25 Jun 2008
Posts: 13

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06 Oct 2008, 02:05
1
KUDOS
j can also be 1 and in that case the remainder will be 1... therefore C is correct
Retired Moderator
Joined: 05 Jul 2006
Posts: 1747

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06 Oct 2008, 02:11
jimmyjamesdonkey wrote:
Can anyone solve this not picking #s, and by using logic?

What is the remainder when 25 is divided by positive integer j?

(1) j is even.

(2) j < 9

from 1

25/2 remainder is 1

25/4 remainder is 1

25/6 remainder is 1

25/10 remainder is 5.......multiple solutions ...insuff

from 2

25/8 remainder is 1

25/7 remainder is 4........insuff

combining

remiander of 25 when devided by (2,4,6,8) is 1 suff

my naswer is d
Retired Moderator
Joined: 05 Jul 2006
Posts: 1747

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06 Oct 2008, 07:10
domleon wrote:
you mean c..

my bad , yes c. killer mistakes
Senior Manager
Joined: 04 Jan 2006
Posts: 276

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06 Oct 2008, 10:50
jimmyjamesdonkey wrote:
Can anyone solve this not picking #s, and by using logic?

What is the remainder when 25 is divided by positive integer j?

(1) j is even.

(2) j < 9

Y = pX + q
Y = numerator
X = denominator
q = remainder

25 = p(X) + q

(1) j is even
25 = p(X) + q
25 / X = p + q / X

X = 2; 25 / 2 = 12 + 1/2; q = 1
X = 4; 25 / 4 = 6 + 1/4; q = 1
X = 6; 25 / 6 = 4 + 1/6; q = 1
X = 8; 25 / 8 = 3 + 1/8; q = 1
X = 10; 25 / 10 = 2 + 5/10; q = 5

There are two answers for the remainder. Insufficient.

(2) j < 9
X =1; 25 / 1 = 25 + 0; q = 0
X = 2; 25 /2 = 12 + 1/2; q = 1

There are two answers for the remainder. Insufficient.

(1) & (2)
All even integers that are less than 9 give the remainder = 1. Sufficient.

Director
Joined: 27 Jun 2008
Posts: 538
WE 1: Investment Banking - 6yrs

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06 Oct 2008, 11:17
Agree with C.

I worked with numbers though.
Re: MGMAT Problem 2.   [#permalink] 06 Oct 2008, 11:17
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# MGMAT Problem 2.

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