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Juaz
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Mike and Ted are among the nine players a basketball coach 08 May 2007, 02:18
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Mike and Ted are among the nine players a basketball coach can choose from to field a five-player team. If all five players are chosen at random, what is the probability of choosing a team that includes Mike and Ted?


1/9
1/6
2/9
5/18
1/3



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Mike and Ted are among the nine players a basketball coach 13 Sep 2007, 12:33
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[/quote]

How do you come up with 7c3
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KillerSquirrel
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Mike and Ted are among the nine players a basketball coach 13 Sep 2007, 12:56
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9C5 = 126 ---> choosing five items out of nine.

7C3 = 35 ---> choosing three items out of seven.

the logic is simple:

since two items have to be in the team (i.e probability = 1) then we only have to find the probability of the other three items (i.e 7C3)

1*7C3/9C5 = 35/126 = 5/18

:)
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demmy
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Mike and Ted are among the nine players a basketball coach 13 Sep 2007, 13:17
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Actually .. I don't follow. Can you please re-iterate that.


Thx
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KillerSquirrel
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Mike and Ted are among the nine players a basketball coach 13 Sep 2007, 13:44
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demmy
Actually .. I don't follow. Can you please re-iterate that.


Thx
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Can you please write what do you find the hardest to understand - so I can focus my explanation.

Thanks

:)
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demmy
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Mike and Ted are among the nine players a basketball coach 13 Sep 2007, 13:50
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Just how you get the 7C3. 9C5 I understand. Many thanks.
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KillerSquirrel
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Mike and Ted are among the nine players a basketball coach Updated on: 13 Sep 2007, 14:11
Originally posted by KillerSquirrel on 13 Sep 2007, 14:05.
Last edited by KillerSquirrel on 13 Sep 2007, 14:11, edited 1 time in total.
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demmy
Just how you get the 7C3. 9C5 I understand. Many thanks.
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You need to choose five players out of nine. But two of those players are already known to be Mike and Ted, so the probability of choosing Mike and Ted is 100% = 1. All you need to do is to find the probability for the other three players (since there are five players in the team). Choosing three players out of seven (excluding Mike and Ted) is 7C3 = 35.

:)
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demmy
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Mike and Ted are among the nine players a basketball coach 13 Sep 2007, 14:08
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KillerSquirrel
demmy
Just how you get the 7C3. 9C5 I understand. Many thanks.

You need to choose five players out of nine. But two of those players are already know to be Mike and Ted, so the probability of choosing Mike and Ted is 100% = 1. All you need to do is to find the probability for the other three players (since there are five players in the team). Choosing three players out of seven (excluding Mike and Ted) is 7C3 = 35.

:)
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Much Appreciated..Thanks man



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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