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Mike makes 7 phone calls on the first day of a local fundraising drive

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Mike makes 7 phone calls on the first day of a local fundraising drive  [#permalink]

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New post 13 Apr 2018, 03:18
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Question Stats:

91% (01:10) correct 9% (00:29) wrong based on 35 sessions

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Mike makes 7 phone calls on the first day of a local fundraising drive and increases the number of calls he makes by 4 calls each day for the 10-day drive. What is the average number of calls he makes during the drive?

A. 25
B. 27
C. 28
D. 50
E. 54

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Re: Mike makes 7 phone calls on the first day of a local fundraising drive  [#permalink]

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New post 13 Apr 2018, 03:34
Since the increase is constant and the total number of days = 10 days which is even.
Hence the average can simply be calculated by taking mean of 5th and 6th day which is 7+(4*4) & 7+(4*6)= (23,37)
So the average = (23+27)/2 = 25. Option A. 25
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Mike makes 7 phone calls on the first day of a local fundraising drive  [#permalink]

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New post 14 Apr 2018, 18:01
Bunuel wrote:
Mike makes 7 phone calls on the first day of a local fundraising drive and increases the number of calls he makes by 4 calls each day for the 10-day drive. What is the average number of calls he makes during the drive?

A. 25
B. 27
C. 28
D. 50
E. 54

After the first day of 7 calls, he increases each day's number of calls by 4 for 9 days. It's an arithmetic progression, whose average =

\(\frac{FirstTerm+LastTerm}{2}\)

First term = 7
Last term* = (7 + (9*4)) = (7 + 36) = 43
Or just list terms: 7,11,15,19,23,27,31,35,39,43

\(\frac{7+43}{2}=25\)

Answer A

\(A_{n} = A_1 + (n-1)d\)
\(A_{10} = 7 + (9)*(4) = 43\)

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Re: Mike makes 7 phone calls on the first day of a local fundraising drive  [#permalink]

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New post 28 Apr 2018, 18:04
4 is getting added to every term
So it is an AP
First term=4
Last term=7+9*4=43

Avg=(7+43)/2=25

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Re: Mike makes 7 phone calls on the first day of a local fundraising drive &nbs [#permalink] 28 Apr 2018, 18:04
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