Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 26 May 2017, 14:04

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Mixture X contains 60% water and 40% chloride. If 120 gallon

Author Message
TAGS:

### Hide Tags

Intern
Joined: 18 Aug 2010
Posts: 3
Followers: 0

Kudos [?]: 5 [1] , given: 0

Mixture X contains 60% water and 40% chloride. If 120 gallon [#permalink]

### Show Tags

02 Dec 2010, 15:12
1
KUDOS
4
This post was
BOOKMARKED
00:00

Difficulty:

(N/A)

Question Stats:

85% (02:31) correct 15% (02:53) wrong based on 32 sessions

### HideShow timer Statistics

Mixture X contains 60% water and 40% chloride. If 120 gallons of Mixture Y is added to 80 gallons of mixture X in order to produce a solution that contains 75% water and 25% chloride, how many gallons of water must mixture Y contain?

[Reveal] Spoiler:
there are 72 gal of water and 48 gal of chloride in mixture X
mix x: 72+48=120
add 80 gal of mixture y
mix y: (80-x)+x = 80
total: 150 + 50 = 200
total water: 72+80-x=150
total chloride: 48+x=50
x=2 in both cases
therefore: mixture y should have 78 gallons of water

the solutions say mixture y should have 102 gallons of water

i'm confused
thanks!
grind
Math Expert
Joined: 02 Sep 2009
Posts: 38908
Followers: 7739

Kudos [?]: 106240 [5] , given: 11618

### Show Tags

02 Dec 2010, 15:43
5
KUDOS
Expert's post
grindcore wrote:
hey guys, i was doing a mixtures problem and got confused looking at the solutions

Question
Mixture X contains 60% water and 40% chloride. If 120 gallons of Mixture Y is added to 80 gallons of mixture X in order to produce a solution that contains 75% water and 25% chloride, how many gallons of water must mixture Y contain?

there are 72 gal of water and 48 gal of chloride in mixture X
mix x: 72+48=120
add 80 gal of mixture y
mix y: (80-x)+x = 80
total: 150 + 50 = 200
total water: 72+80-x=150
total chloride: 48+x=50
x=2 in both cases
therefore: mixture y should have 78 gallons of water

the solutions say mixture y should have 102 gallons of water

i'm confused
thanks!
grind

Provide answer choices for PS questions.

Also:
Please post PS questions in the PS subforum: gmat-problem-solving-ps-140/
Please post DS questions in the DS subforum: gmat-data-sufficiency-ds-141/

No posting of PS/DS questions is allowed in the main Math forum.

As for the question:
Mixture X contains 60% water and 40% chloride. If 120 gallons of Mixture Y is added to 80 gallons of mixture X in order to produce a solution that contains 75% water and 25% chloride, how many gallons of water must mixture Y contain?

Final mixture is Y+X=120+80=200 gallons. We want it to contain 75% water or 0.75*200=150 gallons of water. Now, 80 gallons of mixture X will provide 0.6*80=48 gallons of water, so the rest or 150-48=102 gallons of water should provide mixture Y.

You confused mixture X with mixture Y.

Hope it's clear.
_________________
Intern
Joined: 18 Aug 2010
Posts: 3
Followers: 0

Kudos [?]: 5 [0], given: 0

### Show Tags

02 Dec 2010, 15:53
im so sorry i feel stupid now.
lesson learned.
thanks
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 15466
Followers: 649

Kudos [?]: 209 [0], given: 0

Re: Mixture X contains 60% water and 40% chloride. If 120 gallon [#permalink]

### Show Tags

25 Oct 2013, 03:00
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
MBA Section Director
Status: Back to work...
Affiliations: GMAT Club
Joined: 22 Feb 2012
Posts: 4320
Location: India
City: Pune
GMAT 1: 680 Q49 V34
GPA: 3.4
Followers: 440

Kudos [?]: 3180 [5] , given: 2302

Re: Mixture X contains 60% water and 40% chloride. If 120 gallon [#permalink]

### Show Tags

26 Oct 2013, 22:04
5
KUDOS
Expert's post
1
This post was
BOOKMARKED
Refer the attached Image
Attachments

Capture.PNG [ 14.7 KiB | Viewed 3020 times ]

_________________
Current Student
Joined: 02 Apr 2012
Posts: 77
Location: United States (VA)
Concentration: Entrepreneurship, Finance
GMAT 1: 680 Q49 V34
WE: Consulting (Consulting)
Followers: 1

Kudos [?]: 55 [0], given: 155

Re: Mixture X contains 60% water and 40% chloride. If 120 gallon [#permalink]

### Show Tags

02 Jun 2014, 08:36
Another approach:
Mixture X provide 32 gallons (40%*80) of chloride of the 25%*200 gallons of chloride of the final mixture (=50 gallons of chloride).
Then mixture Y must provide the rest of 18 gallons to complete that 50 gallons of chloride.
If total of mixture Y (water + chloride) is 120 gallons, then gallons of water in mixture Y = 120 (total mixture) -18 (chloride gallons) = 102 water gallons.
_________________

Encourage cooperation! If this post was very useful, kudos are welcome
"It is our attitude at the beginning of a difficult task which, more than anything else, will affect It's successful outcome" William James

Manager
Joined: 25 Apr 2014
Posts: 149
Followers: 0

Kudos [?]: 59 [0], given: 1474

Re: Mixture X contains 60% water and 40% chloride. If 120 gallon [#permalink]

### Show Tags

29 Jun 2014, 09:05
Narenn wrote:
Refer the attached Image

Hi Narenn,

How did you get the 2 there in Qty X? Kindly explain.
SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1857
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Followers: 51

Kudos [?]: 2172 [0], given: 193

Re: Mixture X contains 60% water and 40% chloride. If 120 gallon [#permalink]

### Show Tags

10 Jul 2014, 02:20
maggie27 wrote:
Narenn wrote:
Refer the attached Image

Hi Narenn,

How did you get the 2 there in Qty X? Kindly explain.

He's using allegation method to solve the problem

Mixture X = 80 gallon & Mixture Y = 120

There ratio = 80:120 = 2:3

From here, the values 2 & 3 are put in the allegation expression constructed
_________________

Kindly press "+1 Kudos" to appreciate

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 15466
Followers: 649

Kudos [?]: 209 [0], given: 0

Re: Mixture X contains 60% water and 40% chloride. If 120 gallon [#permalink]

### Show Tags

18 Aug 2015, 22:30
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 15466
Followers: 649

Kudos [?]: 209 [0], given: 0

Re: Mixture X contains 60% water and 40% chloride. If 120 gallon [#permalink]

### Show Tags

21 Aug 2016, 21:27
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7376
Location: Pune, India
Followers: 2288

Kudos [?]: 15127 [0], given: 224

Re: Mixture X contains 60% water and 40% chloride. If 120 gallon [#permalink]

### Show Tags

21 Aug 2016, 22:29
grindcore wrote:
Mixture X contains 60% water and 40% chloride. If 120 gallons of Mixture Y is added to 80 gallons of mixture X in order to produce a solution that contains 75% water and 25% chloride, how many gallons of water must mixture Y contain?

[Reveal] Spoiler:
there are 72 gal of water and 48 gal of chloride in mixture X
mix x: 72+48=120
add 80 gal of mixture y
mix y: (80-x)+x = 80
total: 150 + 50 = 200
total water: 72+80-x=150
total chloride: 48+x=50
x=2 in both cases
therefore: mixture y should have 78 gallons of water

the solutions say mixture y should have 102 gallons of water

i'm confused
thanks!
grind

80 gallons of Mix X containing 40% chloride + 120 gallons of Mix Y ----> 25% chloride mixture

wA/wB = (cB - cAvg)/(cAvg - cA)

80/120 = (Y - 25)/(25 - 40)
2 * (-15) = 3 * (Y - 25)
Y = 15

So the concentration of chloride in Mix Y is 15%.
In 120 gallons of mix Y, you will have (85/100)*120 = 102 gallons

Check:
http://www.veritasprep.com/blog/2011/04 ... -mixtures/
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for \$199

Veritas Prep Reviews

Director
Joined: 07 Dec 2014
Posts: 670
Followers: 3

Kudos [?]: 138 [1] , given: 3

Re: Mixture X contains 60% water and 40% chloride. If 120 gallon [#permalink]

### Show Tags

22 Aug 2016, 07:48
1
KUDOS
let w=% of water in mixture Y
.6*80+w*120=.75*200
w=.85
.85*120=102 gallons water
Re: Mixture X contains 60% water and 40% chloride. If 120 gallon   [#permalink] 22 Aug 2016, 07:48
Similar topics Replies Last post
Similar
Topics:
Seed mixture X is 40% ryegrass and 60% bluegrass by weight; seed mixtu 2 09 May 2011, 08:34
8 A mixture of 40 liters of milk and water contains 10% water. 11 16 Apr 2017, 13:43
68 Tanks X and Y contain 500 and 200 gallons of water respectiv 30 14 Oct 2016, 14:00
3 Seed mixture X is 40 percent ryegrass and 60 percent bluegra 7 26 Oct 2013, 03:30
202 Seed mixture X is 40 percent ryegrass and 60 percent 41 20 May 2017, 06:33
Display posts from previous: Sort by