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# Mod question.

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Intern
Joined: 17 Aug 2008
Posts: 19

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16 Sep 2008, 05:31
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

This is probably a silly question...if x/|y| = -1, then, x = ?

-y, right?

Director
Joined: 14 Aug 2007
Posts: 704

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16 Sep 2008, 05:35
chalven1 wrote:
This is probably a silly question...if x/|y| = -1, then, x = ?

-y, right?

x = -1 |y|
if y > 0
x = -y
if y < 0
x = y
Intern
Joined: 17 Aug 2008
Posts: 19

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16 Sep 2008, 17:54
I thought modulus of a number is always positive...isn't it? Please let me know guys...Thanks...
Manager
Joined: 04 Sep 2007
Posts: 208

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16 Sep 2008, 20:51
chalven1 wrote:
This is probably a silly question...if x/|y| = -1, then, x = ?

-y, right?

Yes.. You are correct. In the above equation X/lYl, for any value of Y (be it negative of positive), the modulus of Y will turn it into a +ve number. To demonstrate, let us assume that X = 2. For us to arrive at -1, lYl should be a negative value of the same number, which is not going to happen.
2/l-2l = 1. Now, the only way for us to arrive at the "-ve" number on the right side of the equation is to have a numerator that is "-ve", which automatically implies the '-ve' of Y.

-2/l2l = -1.

Hope this helps
SVP
Joined: 17 Jun 2008
Posts: 1507

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18 Sep 2008, 01:42
wizardofwashington wrote:
chalven1 wrote:
This is probably a silly question...if x/|y| = -1, then, x = ?

-y, right?

Yes.. You are correct. In the above equation X/lYl, for any value of Y (be it negative of positive), the modulus of Y will turn it into a +ve number. To demonstrate, let us assume that X = 2. For us to arrive at -1, lYl should be a negative value of the same number, which is not going to happen.
2/l-2l = 1. Now, the only way for us to arrive at the "-ve" number on the right side of the equation is to have a numerator that is "-ve", which automatically implies the '-ve' of Y.

-2/l2l = -1.

Hope this helps

That is not always true though.

Assuming x = -y

case 1: y = -2 and hence x = 2 and x/|y| = 2/2 = 1
case 2: y = 2 and hence x = -2 and x/|y| = -2/2 = -1

Hence, as alpha_plus_gama has explained, x = y if y < 0 and x = -y if y > 0.
Re: Mod question.   [#permalink] 18 Sep 2008, 01:42
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# Mod question.

Moderator: chetan2u

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