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31 Jul 2018, 00:47
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
86% (02:47) correct
14%
(03:18)
wrong
based on 224
sessions
History
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Not Attempted Yet
Monthly rent for units in a certain apartment building is determined by the formula \(k*\frac{5r^2+10t}{f+5}\) where k is a constant, r and t are the number of bedrooms and bathrooms in the unit, respectively, and f is the floor number of the unit. A 2-bedroom, 2-bathroom unit on the first floor is going for $800/month. How much is the monthly rent on a 3-bedroom unit with 1 bathroom on the 3rd floor?
(A) $825
(B) $875
(C) $900
(D) $925
(E) $1,000
(A) $825
(B) $875
(C) $900
(D) $925
(E) $1,000
31 Jul 2018, 01:24
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Bunuel
As we're given all the data we need and just need to plug things in, we'll jump straight into the calculation.
This is a Precise approach.
Since r = 2, t = 2, f = 1 give a rent of 800, then plugging in the numbers gives
800 = k * (5*4 + 20)/(1+5) --> 800 = 40k/6 --> 20 = k/6 --> k = 120
So, if r = 3, t = 1, and f = 3 then the rent is
120(5*9+10)/(3+5) = 120*55/8 = 15*55 = 550 + 275 = 825
(A) is our answer.
31 Jul 2018, 03:53
Kudos
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Bunuel
First case :
r = 2, t = 2, f = 1, Rent = 800
On solving we get:
800 = (k * (5 * 4 + 20 )) / ( 1 + 5 )
800 = 40k / 6
40k = 800 * 6
k = 4800 / 40
k = 120
Second case :
r = 3, t = 1, f = 3, k = 120
On solving we get:
Rent = (120 * ( 5 * 9 + 10 )) / ( 3 + 5 )
Rent = (120 * 55) / 8
Rent = 6600 / 8 = 825
Hence, A.
