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Bunuel
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why cant it be 6*6+6.5*6 for total
bv8562
Movie tickets were sold for what average price in Alpha City in 1999?

(1) During the first six months of 1999, the average price of a movie ticket sold in Alpha City was $6.00
(2) During the last six months of 1999, the average price of a movie ticket sold in Alpha City was $6.50

Solution:
This is a weighted average question. I failed to recognize this when I first attempted the question and got it wrong.

(1) During the first six months of 1999, the average price of a movie ticket sold in Alpha City was $6.00

Let,
the # of tickets sold in first half of the year 1999 be = x
the # of tickets sold in second half of the year 1999 be = y
the average price for the first half of the year 1999 be = m
the average price for the first half of the year 1999 be = n

\(\frac{xm+yn}{x+y}=?\)

From statement 1, we have: \(\frac{x6+yn}{x+y}=?\)

Not sufficient as need to know the values of x,y, and n. Eliminate A and D.

(2) During the last six months of 1999, the average price of a movie ticket sold in Alpha City was $6.50

\(\frac{xm+yn}{x+y}=?\)

From statement 2, we have: \(\frac{xm+y*6.5}{x+y}=?\)

Not sufficient as need to know the values of x,y, and m. Eliminate B..

Statements 1 & 2 together:

we have: \(\frac{x*6+y*6.5}{x+y}=?\)

Not sufficient as we still do not know the values of x & y. Therefore, E.
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why cant it be 6*6+6.5*6 for total
bv8562
Movie tickets were sold for what average price in Alpha City in 1999?

(1) During the first six months of 1999, the average price of a movie ticket sold in Alpha City was $6.00
(2) During the last six months of 1999, the average price of a movie ticket sold in Alpha City was $6.50

Solution:
This is a weighted average question. I failed to recognize this when I first attempted the question and got it wrong.

(1) During the first six months of 1999, the average price of a movie ticket sold in Alpha City was $6.00

Let,
the # of tickets sold in first half of the year 1999 be = x
the # of tickets sold in second half of the year 1999 be = y
the average price for the first half of the year 1999 be = m
the average price for the first half of the year 1999 be = n

\(\frac{xm+yn}{x+y}=?\)

From statement 1, we have: \(\frac{x6+yn}{x+y}=?\)

Not sufficient as need to know the values of x,y, and n. Eliminate A and D.

(2) During the last six months of 1999, the average price of a movie ticket sold in Alpha City was $6.50

\(\frac{xm+yn}{x+y}=?\)

From statement 2, we have: \(\frac{xm+y*6.5}{x+y}=?\)

Not sufficient as need to know the values of x,y, and m. Eliminate B..

Statements 1 & 2 together:

we have: \(\frac{x*6+y*6.5}{x+y}=?\)

Not sufficient as we still do not know the values of x & y. Therefore, E.


We do not know how many tickets were sold in each half of the year, or even their ratio. If the numbers were the same, then yes, the average would be (6 + 6.5)/2 = 6.25.

Simple examples:

  • If 1 ticket was sold in the first half at $6 and 1 in the second half at $6.5, the average would be (6 + 6.5)/2 = 6.25.
  • If 1 ticket was sold in the first half at $6 and 2 in the second half at $6.5 each, the average would be (6 + 6.5 + 6.5)/3 = 6.33...

So, without knowing the number (or ratio) of tickets sold in each period, the overall average cannot be determined.
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