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28 Sep 2007, 11:47
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N and R are integers. If N is divisible by 10^R, but cannot be divisible by 10^(R+1), R= ?
1) N is divisible by 2^5, but cannot be divisible by 2^6.
1) N is divisible by 5^6, but cannot be divisible by 5^7
1) N is divisible by 2^5, but cannot be divisible by 2^6.
1) N is divisible by 5^6, but cannot be divisible by 5^7
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28 Sep 2007, 12:20
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Ravshonbek
D.
1. From S1 : N can be 160; 480; ...
160/32 - Divisible
160/64 - Not
R=1; 160/10 - Divisible; 160/100 - Not
R=1; 480/10 - Divisible; 480/100 - Not
R has to be 1 to satisfy the question stem and S1.
2. From S2: Any number divisible by a power of 5 ends in a 5.
In order for a number ending in 5 and supporting the condition that it is divisible by 10^R and not by 10^R+1 R has to be 0.
R = 0.
Hence D.
Would be very interested in finding OA.
Updated on: 28 Sep 2007, 13:06
Originally posted by KillerSquirrel on 28 Sep 2007, 12:36.
Last edited by KillerSquirrel on 28 Sep 2007, 13:06, edited 3 times in total.
Last edited by KillerSquirrel on 28 Sep 2007, 13:06, edited 3 times in total.
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the answer is (C)
statement 1
since N divisible by 2^5 but not by 2^6 then N contains no more and no less then 2^5 ---> but we cannot tell how much 5's.
2^5*5^3 = 10^3*2*2 ---> R can be 3
2^5*5^4 = 10^4*2 ---> R can be 4
statement 2
since N divisible by 5^6 but not 5^7 then N contains no more and no less then 5^6 ---> but we cannot tell how much 2's
2^5*5^6 = 10^5*5 ---> R can be 5
2^4*5^6 = 10^4*5*5 ---> R can be 4
both statements
since N divisible by 2^5 and 5^6 then:
5^6*2^5 = 10^5*5 and R has to be 5 !!
the answer is (C)
statement 1
since N divisible by 2^5 but not by 2^6 then N contains no more and no less then 2^5 ---> but we cannot tell how much 5's.
2^5*5^3 = 10^3*2*2 ---> R can be 3
2^5*5^4 = 10^4*2 ---> R can be 4
statement 2
since N divisible by 5^6 but not 5^7 then N contains no more and no less then 5^6 ---> but we cannot tell how much 2's
2^5*5^6 = 10^5*5 ---> R can be 5
2^4*5^6 = 10^4*5*5 ---> R can be 4
both statements
since N divisible by 2^5 and 5^6 then:
5^6*2^5 = 10^5*5 and R has to be 5 !!
the answer is (C)
