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N is a 3-digit positive integer that composed of 1, 2, and 3

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N is a 3-digit positive integer that composed of 1, 2, and 3 [#permalink]

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New post 28 Jul 2008, 02:56
N is a 3-digit positive integer that composed of 1, 2, and 3 without repetition. What is the sum of all such possible numbers?
A. 666
B. 726
C. 999
D. 1,221
E. 1,332

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Re: 3digit positive integer [#permalink]

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New post 28 Jul 2008, 03:11
E.
There are 6 such numbers: 123+132+213+231+312+321=1,332
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haveaniceday

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Re: 3digit positive integer [#permalink]

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New post 28 Jul 2008, 03:15
1332.

Since only 3 digit numbers are there, and that too without rep, i just wrote all of them and added.

123+132+231+213+312+321=1332.

o/w it would be an interesting problem. I would rely on guess work. Here is my take on how i would go about it.

u will have 2 numbers starting with 1. it will give u atleast 100+100.
u " " 2 " " " 2. it will give u atleast 200+200.
"do" 3. it will give u atleast 300+300.

total would give u atleast 1200. there are two numbers greater than 1200. so go for the next level, 10s place with the largest option.
with 1, u will have 30+20 atleast.. that itself puts u above 1250. so u can directly go to e.


I am sure, the gurus out here will be able to suggest better approach though
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Re: 3digit positive integer [#permalink]

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New post 28 Jul 2008, 09:06
1
arjtryarjtry wrote:
N is a 3-digit positive integer that composed of 1, 2, and 3 without repetition. What is the sum of all such possible numbers?
A. 666
B. 726
C. 999
D. 1,221
E. 1,332


E

For each digit:
possible number are 1, 2,3 and each will appear twice:
123
132
213
231
312
321

If you see the sum of each column is 1+1+2+2+3+3 = 12
so ans is
12+120+1200= 1332
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Re: 3digit positive integer [#permalink]

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New post 28 Jul 2008, 09:09
arjtryarjtry wrote:
N is a 3-digit positive integer that composed of 1, 2, and 3 without repetition. What is the sum of all such possible numbers?
A. 666
B. 726
C. 999
D. 1,221
E. 1,332


E) 123 + 132 + 213 + 231 + 312 + 321 = 1332

Faster calc. can be Sum of units digit = 12, Sum of tens digit = 12 and sum of hundreds digit = 12 which makes it 1332
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Re: 3digit positive integer [#permalink]

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New post 28 Jul 2008, 09:47
arjtryarjtry wrote:
N is a 3-digit positive integer that composed of 1, 2, and 3 without repetition. What is the sum of all such possible numbers?
A. 666
B. 726
C. 999
D. 1,221
E. 1,332


whenever i see a symetric problem like this..

i just focus on 1 digit as the sum of the that digit would 10 times that for 10s, 100 times for hundreds and so on..

123
132
231
213
312
321
just focus on the unit digit.. 3+2+1+3+2+1 i.e 3*2 + 2*2 + 2*1=12

1200+120+12
1332
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Re: 3digit positive integer [#permalink]

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New post 29 Jul 2008, 10:15
fresinha... good tip... i think there is a prob similar to this somewhere here with the heading GMATPREP

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: 3digit positive integer   [#permalink] 29 Jul 2008, 10:15
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