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28 Jul 2008, 02:56
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N is a 3-digit positive integer that composed of 1, 2, and 3 without repetition. What is the sum of all such possible numbers?
A. 666
B. 726
C. 999
D. 1,221
E. 1,332
A. 666
B. 726
C. 999
D. 1,221
E. 1,332
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28 Jul 2008, 03:11
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E.
There are 6 such numbers: 123+132+213+231+312+321=1,332
There are 6 such numbers: 123+132+213+231+312+321=1,332
28 Jul 2008, 03:15
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1332.
Since only 3 digit numbers are there, and that too without rep, i just wrote all of them and added.
123+132+231+213+312+321=1332.
o/w it would be an interesting problem. I would rely on guess work. Here is my take on how i would go about it.
u will have 2 numbers starting with 1. it will give u atleast 100+100.
u " " 2 " " " 2. it will give u atleast 200+200.
"do" 3. it will give u atleast 300+300.
total would give u atleast 1200. there are two numbers greater than 1200. so go for the next level, 10s place with the largest option.
with 1, u will have 30+20 atleast.. that itself puts u above 1250. so u can directly go to e.
I am sure, the gurus out here will be able to suggest better approach though
Since only 3 digit numbers are there, and that too without rep, i just wrote all of them and added.
123+132+231+213+312+321=1332.
o/w it would be an interesting problem. I would rely on guess work. Here is my take on how i would go about it.
u will have 2 numbers starting with 1. it will give u atleast 100+100.
u " " 2 " " " 2. it will give u atleast 200+200.
"do" 3. it will give u atleast 300+300.
total would give u atleast 1200. there are two numbers greater than 1200. so go for the next level, 10s place with the largest option.
with 1, u will have 30+20 atleast.. that itself puts u above 1250. so u can directly go to e.
I am sure, the gurus out here will be able to suggest better approach though
