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N is a 3-digit positive integer that composed of 1, 2, and 3 [#permalink]

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28 Jul 2008, 01:56

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

N is a 3-digit positive integer that composed of 1, 2, and 3 without repetition. What is the sum of all such possible numbers? A. 666 B. 726 C. 999 D. 1,221 E. 1,332

Since only 3 digit numbers are there, and that too without rep, i just wrote all of them and added.

123+132+231+213+312+321=1332.

o/w it would be an interesting problem. I would rely on guess work. Here is my take on how i would go about it.

u will have 2 numbers starting with 1. it will give u atleast 100+100. u " " 2 " " " 2. it will give u atleast 200+200. "do" 3. it will give u atleast 300+300.

total would give u atleast 1200. there are two numbers greater than 1200. so go for the next level, 10s place with the largest option. with 1, u will have 30+20 atleast.. that itself puts u above 1250. so u can directly go to e.

I am sure, the gurus out here will be able to suggest better approach though

N is a 3-digit positive integer that composed of 1, 2, and 3 without repetition. What is the sum of all such possible numbers? A. 666 B. 726 C. 999 D. 1,221 E. 1,332

E

For each digit: possible number are 1, 2,3 and each will appear twice: 123 132 213 231 312 321

If you see the sum of each column is 1+1+2+2+3+3 = 12 so ans is 12+120+1200= 1332

N is a 3-digit positive integer that composed of 1, 2, and 3 without repetition. What is the sum of all such possible numbers? A. 666 B. 726 C. 999 D. 1,221 E. 1,332

E) 123 + 132 + 213 + 231 + 312 + 321 = 1332

Faster calc. can be Sum of units digit = 12, Sum of tens digit = 12 and sum of hundreds digit = 12 which makes it 1332

N is a 3-digit positive integer that composed of 1, 2, and 3 without repetition. What is the sum of all such possible numbers? A. 666 B. 726 C. 999 D. 1,221 E. 1,332

whenever i see a symetric problem like this..

i just focus on 1 digit as the sum of the that digit would 10 times that for 10s, 100 times for hundreds and so on..

123 132 231 213 312 321 just focus on the unit digit.. 3+2+1+3+2+1 i.e 3*2 + 2*2 + 2*1=12