Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2601:30 AM EDT
-02:30 AM EDT
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
Apr 2912:30 AM EDT
-01:30 AM EDT
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
May 0111:00 AM PDT
-12:00 PM PDT
Free- full-length test + 15 concept videos + 150+ short videos + study plan!
May 0306:30 AM PDT
-08:30 AM PDT
Verbal trouble on GMAT? Fix it NOW! Join Sunita Singhvi for a focused webinar on actionable strategies to boost your Verbal score and take your performance to the next level.
Updated on: 01 Sep 2017, 09:30
Originally posted by Jinglander on 24 May 2010, 22:58.
Last edited by Bunuel on 01 Sep 2017, 09:30, edited 2 times in total.
Last edited by Bunuel on 01 Sep 2017, 09:30, edited 2 times in total.
Renamed the topic, edited the question and added the OA.
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
56% (01:44) correct
44%
(01:30)
wrong
based on 299
sessions
History
Date
Time
Result
Not Attempted Yet
If N is a positive integer, is 9 a factor of N?
(1) 18 is a factor of N^2
(2) 27 is a factor of N^3
(1) 18 is a factor of N^2
(2) 27 is a factor of N^3
Experience GMAT Club Test Questions
Yes, you've landed on a GMAT Club Tests question
Craving more? Unlock our full suite of GMAT Club Tests here
Want to experience more? Get a taste of our tests with our free trial today
Rise to the challenge with GMAT Club Tests. Happy practicing!
25 May 2010, 03:43
Kudos
Bookmarks
If \(n\) is a positive integer, is 9 a factor of \(n\) ?
Given: \(n\) is a positive integer. The question is: can \(n\) be expressed as \(n=9k\), where \(k\) is a positive integer?
(1) 18 is a factor of \(n^2\).
From the given information, \(n^2 = 18p\), where \(p\) is a positive integer. This means \(n = 3\sqrt{2p}\). Since \(n\) must be an integer, \(\sqrt{2p}\) must also be an integer, specifically one with even values. Therefore, \(n = 3\sqrt{2p}\) can take values that are multiples of \(3*2 = 6\), such as 6, 12, 18, etc. Based on this, \(n\) might or might not be a multiple of 9. Not sufficient.
(2) 27 is a factor of \(n^3\).
From the given information, \(n^3 = 27q\), where \(q\) is a positive integer. This means \(n = 3\sqrt[3]{q}\). Since \(n\) is an integer, \(\sqrt[3]{q}\) must also be an integer. Therefore, \(n = 3\sqrt[3]{q}\) can take values that are multiples of 3, such as 3, 6, 9, 12, etc. Thus, \(n\) might or might not be a multiple of 9. Not sufficient.
(1)+(2) From (1), we know that \(n\) is a positive multiple of 6. From (2), we know that \(n\) is a positive multiple of 3. Combining these pieces of information, we only know that \(n\) is a positive multiple of 6, and thus \(n\) could be 6, 12, 18, etc. This means that \(n\) might or might not be a multiple of 9. Not sufficient.
Answer: E
Given: \(n\) is a positive integer. The question is: can \(n\) be expressed as \(n=9k\), where \(k\) is a positive integer?
(1) 18 is a factor of \(n^2\).
From the given information, \(n^2 = 18p\), where \(p\) is a positive integer. This means \(n = 3\sqrt{2p}\). Since \(n\) must be an integer, \(\sqrt{2p}\) must also be an integer, specifically one with even values. Therefore, \(n = 3\sqrt{2p}\) can take values that are multiples of \(3*2 = 6\), such as 6, 12, 18, etc. Based on this, \(n\) might or might not be a multiple of 9. Not sufficient.
(2) 27 is a factor of \(n^3\).
From the given information, \(n^3 = 27q\), where \(q\) is a positive integer. This means \(n = 3\sqrt[3]{q}\). Since \(n\) is an integer, \(\sqrt[3]{q}\) must also be an integer. Therefore, \(n = 3\sqrt[3]{q}\) can take values that are multiples of 3, such as 3, 6, 9, 12, etc. Thus, \(n\) might or might not be a multiple of 9. Not sufficient.
(1)+(2) From (1), we know that \(n\) is a positive multiple of 6. From (2), we know that \(n\) is a positive multiple of 3. Combining these pieces of information, we only know that \(n\) is a positive multiple of 6, and thus \(n\) could be 6, 12, 18, etc. This means that \(n\) might or might not be a multiple of 9. Not sufficient.
Answer: E
General Discussion
25 May 2010, 07:11
Kudos
Bookmarks
I will post in the right place from now on. Also in part 1 why only take the even integers to realize is was a multiple of 6
Posted from my mobile device
Posted from my mobile device
